If the system given has parallel lines, what is the answer?
2 answers:
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Answer:
Jane is 14
Step-by-step explanation:
The age of each person increases by a fractional amount. In order to find Jane's age, you will need to start with Ari's age and then add the additional fractional amounts. In order to add with fractions, the denominators must be the same. In the case of Glen, you can figure his age out first:
12 + 1
5 and 6 have a common denominator of 30, so multiply the numerator and denominator by the same factor and than add:
12 = 12
+ 1
or 1
= 13
Taking Glen's age and adding the additional amount for Jane:
13 + 1
or 1
=14
Answer:
18 kilograms of 30% copper alloy is mixed with 72 kilograms of 55% copper alloy to makes 90 kg of a 50% copper alloy .
Step-by-step explanation:
Let us assume that the kilogram of 30% copper used to make alloy be x .
Let us assume that the kilogram of 55% copper used to make alloy be y .
As given
A metalworker has a metal alloy that is 30% copper and another alloy that is 55% copper.
The metalworker combine to create 90 kg of a 50% copper alloy .
Equation becomes
x + y = 90
30% is written in the decimal form .
= 0.30
55% is written in the decimal form .
= 0.55
50% is written in the decimal form .
= 0.50
Equation becomes
Concentration of 30% copper alloy × Number of kilograms of 30% copper alloy used + Concentration of 55% copper alloy × Number of kilograms of 55% copper alloy used = Concentration of 50% copper alloy × Number of kilograms of 50% copper alloy .
0.30x + 0.55y = 0.50 × 90
Simplify the above equation
30x + 55y = 4500
Two equation becomes
x + y = 90
30x + 55y = 4500
Multiply x + y = 90 by 30 and subtracted form 30x + 55y = 4500 .
30x - 30x + 55y - 30y = 4500 - 2700
25y = 1800
y = 72 kilograms
Putting the value of y in the equation .
x + 72 = 90
x = 90 - 72
x = 18 kilograms
Therefore 18 kilograms of 30% copper alloy is mixed with 72 kilograms of 55% copper alloy to makes 90 kg of a 50% copper alloy .
Answer:
(f-g)(x) = -x² +4x +6
Step-by-step explanation:
We assume you want to find (f -g)(x).