Answer: C. the product of 6 and the difference of x minus 5
62 is the answer
hope i helped
Answer:
J) 2.4
Step-by-step explanation:
8[6.3-4(1.5)] Simplify the expression 2.4
Answer:
The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30° ⇒ last answer
Step-by-step explanation:
In any triangle if the sum of the squares of the shortest two sides is equal to the square of the longest side, then the triangle is a right triangle and the angle opposite to the longest side is the right angle
In Δ VUW
∵ WV = 6 cm
∵ WU = 3
cm
∵ UV = 3 cm
- Use the rule above tho check if it is a right Δ or not
∴ The longest side is WV
∴ The shortest two sides are WU and UV
∵ (WV)² = (6)² = 36
∵ (WU)² + (UV)² = (3
)² + (3)² = 27 + 9 = 36
∴ (WV)² = (WU)² + (UV)²
- That means ∠U which opposite to WV is a right angle
∴ Δ VUW is a right triangle at ∠U
∴ m∠U = 90°
Let us use the trigonometry ratios to find m∠W and m∠V
→ sin Ф =
∵ UV is the opposite side of ∠W
∵ WV is the hypotenuse
∵ sin(∠W) = 
∵ sin(∠W) = 
- Use
to find ∠W
∴ ∠W = 
∴ m∠W = 30°
∵ WU is the opposite side of ∠V
∵ WV is the hypotenuse
∵ sin(∠V) = 
∵ sin(∠V) = 
- Use
to find ∠V
∴ ∠V = 
∴ m∠V = 60°
The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30°
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
brainly.com/question/15161224
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