There is the answer hope it helpd if you can mark me brainliest
Let's simplify step-by-step.<span><span><span><span>5<span>x2</span></span>−<span>3x</span></span>−2</span>−<span>(<span><span><span>−<span>2<span>x2</span></span></span>−x</span>+10</span>)</span></span>Distribute the Negative Sign:<span>=<span><span><span><span>5<span>x2</span></span>−<span>3x</span></span>−2</span>+<span><span>−1</span><span>(<span><span><span>−<span>2<span>x2</span></span></span>−x</span>+10</span>)</span></span></span></span><span>=<span><span><span><span><span><span><span><span>5<span>x2</span></span>+</span>−<span>3x</span></span>+</span>−2</span>+<span><span>−1</span><span>(<span>−<span>2<span>x2</span></span></span>)</span></span></span>+<span><span>−1</span><span>(<span>−x</span>)</span></span></span>+<span><span>(<span>−1</span>)</span><span>(10)</span></span></span></span><span>=<span><span><span><span><span><span><span><span><span>5<span>x2</span></span>+</span>−<span>3x</span></span>+</span>−2</span>+<span>2<span>x2</span></span></span>+x</span>+</span>−10</span></span>Combine Like Terms:<span>=<span><span><span><span><span><span>5<span>x2</span></span>+<span>−<span>3x</span></span></span>+<span>−2</span></span>+<span>2<span>x2</span></span></span>+x</span>+<span>−10</span></span></span><span>=<span><span><span>(<span><span>5<span>x2</span></span>+<span>2<span>x2</span></span></span>)</span>+<span>(<span><span>−<span>3x</span></span>+x</span>)</span></span>+<span>(<span><span>−2</span>+<span>−10</span></span>)</span></span></span><span>=<span><span><span>7<span>x2</span></span>+<span>−<span>2x</span></span></span>+<span>−12</span></span></span>Answer:<span>=<span><span><span>7<span>x2</span></span>−<span>2x</span></span>−<span>12</span></span></span>
Answer:
t=0 or t=-1/2
Step-by-step explanation:
Solve for t over the real numbers:
t (2 t + 1) = 0
Split into two equations:
t = 0 or 2 t + 1 = 0
Subtract 1 from both sides:
t = 0 or 2 t = -1
Divide both sides by 2:
Answer: |
| t = 0 or t = -1/2
first off, make sure you have a Unit Circle, if you don't do get one, you'll need it, you can find many online.
let's double up 67.5°, that way we can use the half-angle identity for the cosine of it, so hmmm twice 67.5 is simply 135°, keeping in mind that 135° is really 90° + 45°, and that whilst 135° is on the 2nd Quadrant and its cosine is negative 67.5° is on the 1st Quadrant where cosine is positive, so
![cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta) \\\\\\ cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos(135^o)\implies cos(90^o+45^o)\implies cos(90^o)cos(45^o)~~ - ~~sin(90^o)sin(45^o) \\\\\\ \left( 0 \right)\left( \cfrac{\sqrt{2}}{2} \right)~~ - ~~\left( 1\right)\left( \cfrac{\sqrt{2}}{2} \right)\implies -\cfrac{\sqrt{2}}{2} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=cos%28%5Calpha%20%2B%20%5Cbeta%29%3D%20cos%28%5Calpha%29cos%28%5Cbeta%29-%20sin%28%5Calpha%29sin%28%5Cbeta%29%20%5C%5C%5C%5C%5C%5C%20cos%5Cleft%28%5Ccfrac%7B%5Ctheta%7D%7B2%7D%5Cright%29%3D%5Cpm%20%5Csqrt%7B%5Ccfrac%7B1%2Bcos%28%5Ctheta%29%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20cos%28135%5Eo%29%5Cimplies%20cos%2890%5Eo%2B45%5Eo%29%5Cimplies%20cos%2890%5Eo%29cos%2845%5Eo%29~~%20-%20~~sin%2890%5Eo%29sin%2845%5Eo%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28%200%20%5Cright%29%5Cleft%28%20%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5Cright%29~~%20-%20~~%5Cleft%28%201%5Cright%29%5Cleft%28%20%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5Cright%29%5Cimplies%20-%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer:
Man's in Ce
Step-by-step explanation:
