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Tamiku [17]
3 years ago
9

If sin α + cos α = 1.2, find sin α · cos α THANKS! (:

Mathematics
1 answer:
algol [13]3 years ago
5 0
Is there supposed to me a picture or what?
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The expression 6(x − 5) means the
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Answer: C. the product of 6 and the difference of x minus 5
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How much is 54 + 12 = ?
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62 is the answer
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5 0
3 years ago
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Pls helppp I will mark brainlist if correct !! :)
klemol [59]

Answer:

J) 2.4

Step-by-step explanation:

8[6.3-4(1.5)] Simplify the expression 2.4

5 0
3 years ago
Triangle V U W is shown. The length of side W V is 6 centimeters, the length of side W U is 3 StartRoot 3 EndRoot centimeters, a
Nat2105 [25]

Answer:

The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30° ⇒ last answer

Step-by-step explanation:

In any triangle if the sum of the squares of the shortest two sides is equal to the square of the longest side, then the triangle is a right triangle and the angle opposite to the longest side is the right angle

In Δ VUW

∵ WV = 6 cm

∵ WU = 3\sqrt{3} cm

∵ UV = 3 cm

- Use the rule above tho check if it is a right Δ or not

∴ The longest side is WV

∴ The shortest two sides are WU and UV

∵ (WV)² = (6)² = 36

∵ (WU)² + (UV)² = (3\sqrt{3} )² + (3)² = 27 + 9 = 36

∴ (WV)² =  (WU)² + (UV)²

- That means ∠U which opposite to WV is a right angle

∴ Δ VUW is a right triangle at ∠U

∴ m∠U = 90°

Let us use the trigonometry ratios to find m∠W and m∠V

→ sin Ф = \frac{opposite}{hypotenuse}

∵ UV is the opposite side of ∠W

∵ WV is the hypotenuse

∵ sin(∠W) = \frac{UV}{WV}

∵ sin(∠W) = \frac{3}{6}=\frac{1}{2}

- Use sin^{-1} to find ∠W

∴ ∠W = sin^{-1}(\frac{1}{2})

∴ m∠W = 30°

∵ WU is the opposite side of ∠V

∵ WV is the hypotenuse

∵ sin(∠V) = \frac{WU}{WV}

∵ sin(∠V) = \frac{3\sqrt{3}}{6}=\frac{\sqrt{3}}{2}

- Use sin^{-1} to find ∠V

∴ ∠V = sin^{-1}(\frac{\sqrt{3}}{2})

∴ m∠V = 60°

The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30°

6 0
3 years ago
Read 2 more answers
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

#SPJ1

7 0
2 years ago
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