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Solnce55 [7]
3 years ago
5

4(g+2 )+8g=56 show work

Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0
4(g+2)+8g=56
4g+8+8g=56
12g+8=56
12g-8=56-8
12g= 48
12g/12=48/12
g=4

Steps
1. Distribute by multiply 4 times g and 4 time 2
2.do the opposite of either add or subtraction in this case is opposite of add which is subtract
3.divide both side by the coefficient where it has the letter for example in this case is 12g so you divide 12g/12=12/48
Which gives you the answer 4
Bingel [31]3 years ago
5 0
4g+8+8g=56
12g+8=56
12g+-8=-8
12g=48
DIVIDE 12 TO BOTH 
g=4
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gizmo_the_mogwai [7]

Answer:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

\bar X_{1}=9.1 represent the mean for the sample 1

\bar X_{2}=8 represent the mean for the sample 2

s_{1}=1.9 represent the sample standard deviation for the sample 1

s_{2}=2.1 represent the sample standard deviation for the sample 2

n_{1}=40 sample size for the group 1

n_{2}=50 sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis:\mu_{1} = \mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604  

Statistical decision

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=40+50-2=88

Since is a bilateral test the p value would be:

p_v =2*P(t_{(88)}>2.604)=0.0108

So the p value is a very low value and using any significance level for given \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0
3 years ago
Consider the functions shown below.
I am Lyosha [343]

Answer: D

<u>Step-by-step explanation:</u>

A. False

f(x): x → -∞, y → -∞

g(x): x → -∞, y → 1  

B. False

at x = -1, f(x) = -7

at x = -1, g(x) = 1.5

C. False

refer to A

g(x) → 1 and f(x) → -∞   so g(x) > f(x)

D. TRUE

It is hard to tell from the graph so plug in a value to check.

f(10) = 5(10) - 2

       = 50 - 2

       = 48

g(10) = 2¹⁰ + 1

        = 1024 + 1

        = 1025

g(10) > f(10)

6 0
3 years ago
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