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never [62]
3 years ago
15

The rhythmic note that three beats is called a____half note.

Computers and Technology
2 answers:
aev [14]3 years ago
7 0

Answer:

it is called a dotted half note

Mrrafil [7]3 years ago
4 0
Answer:
Dotted half note
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3 years ago
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List and briefly explain five activities for which a purchasing department normally has responsibility
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5 0
3 years ago
We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is
bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons  to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons  to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons  to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as  one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons  to find the middle terms.

If list has 18 elements, there are two middle terms as  one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons  to find the middle terms.

If list has 20 elements, there are two middle terms as  one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons  to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are  at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0
3 years ago
Construct an algorithm to print the first 20 numbers in the Fibonacci series (in mathematics) thanks
ss7ja [257]

Answer:

0+1=1

1+1=2

1+2=3

2+3=5

3+5=8

5+8=13

Explanation:

// C++ program to print

// first n Fibonacci numbers

#include <bits/stdc++.h>

using namespace std;

 

// Function to print

// first n Fibonacci Numbers

void printFibonacciNumbers(int n)

{

   int f1 = 0, f2 = 1, i;

 

   if (n < 1)

       return;

   cout << f1 << " ";

   for (i = 1; i < n; i++) {

       cout << f2 << " ";

       int next = f1 + f2;

       f1 = f2;

       f2 = next;

   }

}

 

// Driver Code

int main()

{

   printFibonacciNumbers(7);

   return 0;

}

 

8 0
3 years ago
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