Question

Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is: Equal

Answer 1

Answer:

The C++ code is given below with appropriate comments

Explanation:

//Remove this header file if not using visual studio.

#include "stdafx.h"

//Include the required header files.

#include <iostream>

//Use for maths function.

#include <cmath>

using namespace std;

//Define main function

int main()

{

      // Define the variables

      double targetValue = 0.3333;

      double sensorReading = 0.0;

      //Perform the opeartion.

      sensorReading = 1.0 / 3.0;

      // Get the absolute floating point value and

      // Check up to 4 digits.

      if (fabs(sensorReading - targetValue) < 1E-4)

      {

             //Print equal if the values are close enough.

             cout << "Equal" << endl;

      }

      else

      {

             //Print not equal if the values are not                  

             //close enough.

             cout << "Not equal" << endl;

      }

      system("pause");

      //Return the value 0.

      return 0;

}