Using the knowledge in computational language in C code it is possible to write a code that organizes and calculates the value of the matrix of A*A and that is in up to 4 decimal places.
<h3>Writing the code in C is possible:</h3>
<em>A=[1 2 2;3 4 5;6 7 8];</em>
<em>[u ,s ,v] = svd(A);</em>
<em>k = 1;</em>
<em>A1 = u(:,1:k)*s(1:k,1:k)*v(:,1:k)'; %'</em>
<em>RMSE = rms(sqrt(mean((A - A1).^2)))</em>
See more about C code at brainly.com/question/17544466
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Answer:
a. 2^6, or 64 opcodes.
b. 2^5, or 32 registers.
c. 2^16, or 0 to 65536.
d. -32768 to 32768.
Explanation:
a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.
b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.
c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.
d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.
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