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3 years ago

8

It’s a busy lunch hour. Three cashiers are working, and there are 10 total customers in line. The average time to process each s

ales transaction is 110 seconds. How much time will have passed when the last sales transaction is complete?

1 answer:

Ulleksa [173]3 years ago

7 0

Answer:

6.1 minutes

Step-by-step explanation:

I did it on virtual business

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Twenty thousand, two and twelve hundredths written in Numeric Form ?

coldgirl [10]

Answer:

202.12

Step-by-step explanation:

Please mark Me brainliest!

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2 years ago

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Determine whether the polynomial is a difference of squares and if it is, factor it. y2 – 16

luda_lava [24]

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4 years ago

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Gloria is an artist. She sets a goal to paint 2 paintings every month. The number of paintings Gloria creates depends on the num

BartSMP [9]

Answer:

we get the all equation of given condition $M = 2P+1$ & $P=2M+1$ Step-by-step explanation:

Given that,

Number of painting made by Gloria every month is 2.

Gloria creates depends on the number of paintings p, Gloria paints over m months if she meet her goal.

we have to check all the apply.

According to question,

M is the independent variable and P is dependent variable.

So, Relation formed by given statement is $M =2P$

Case(1): P is increased by 2 as M is increased by 1.

Then, $M+1= 2\times (P+2)$

$M+1= 2P+2$

$M = 2P+1$

This is Equation of the given case(1).

Again, P is the independent variable and M is dependent variable.

∴ $P=2M$

Case (2) M is increased by 2 as P increased by 1.

Then, $P+1=2\times(M+2)$

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Hence,

we get the all equation of given condition $M = 2P+1$ & $P=2M+1$

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3 years ago

beks73 [17]

D=dollars earned
T=time spent painting the fence.

(1,5) (2,10) (3,15)

D=5T

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Each day in Bio 18, Derek leaves a stack of paper packets near the entry door for students to obtain. Eighty-one percent of stud

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Answer:

Step-by-step explanation:

This is a binomial probability distribution because there are only 2 possible outcomes. It is either a randomly selected student grabs a packet before being seated or the student sits first before grabbing a packet. The probability of success, p in this scenario would be that a randomly selected student sits first before grabbing a packet. Therefore,

p = 1 - 0.81 = 0.91

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The probability that exactly two students sit first before grabbing a packet, P(x = 2) would be determined from the binomial probability distribution calculator. Therefore,

P(x = 2) = 0.297

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3 years ago