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3 years ago

8

It’s a busy lunch hour. Three cashiers are working, and there are 10 total customers in line. The average time to process each s

ales transaction is 110 seconds. How much time will have passed when the last sales transaction is complete?

1 answer:

Ulleksa [173]3 years ago

7 0

Answer:

6.1 minutes

Step-by-step explanation:

I did it on virtual business

You might be interested in

Can you please help me? as much as you can is greatly appreciated <333 pt 1

zhuklara [117]

Answer:

<em>11) </em><em>80°</em>

<em>12) </em><em>80°</em>

<em>13) </em><em>80°</em>

<em>14) </em><em>40°</em>

<em>15) </em><em>60°</em>

<em>16) </em><em>120°</em>

<em>17) </em><em>180°</em>

<em>18) </em><em>100°</em>

<em>19) </em><em>120°</em>

<em>20) </em><em>280°</em>

Step-by-step explanation:

This will take awhile, so I will just give you the theorems I used to determine my answer.

11) Supplementary angles theorem

12) Central Angles/Arcs Theorem

13) Vertical Angles Theorem

14) Central Angles/Arcs Theorem

15) Vertical Angles Theorem (The vertical angle minus 40 would equal 60)

16) Supplementary Angles Theorem (Supplementary to 100 degrees)

17) Central Angles/Arc Theorem

18) Vertical Angles & Central Angles/Arc Theorem

19) Angle Addition Postulate, somewhat

20) Angle Addition Postulate

<em>Have a nice day, fam. This problem really worked my brain. Spread The Love.</em>

4 0

2 years ago

A telescope contains both a parabolic mirror and a hyperbolic mirror. They share focus , which is 46feet above the vertex of th

uranmaximum [27]

the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.

The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.

In terms of hyperbola, F1F2=2c, c=20.

The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.

Use formula c^2=a^2+b^2c

2

=a

2

+b

2

to find b:

\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}

(20)

2

=(18)

2

+b

2

,

b

2

=400−324=76

.

The branches of hyperbola go in y-direction, so the equation of hyperbola is

\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1

b

2

y

2

−

a

2

x

2

=1 .

Substitute a and b:

\dfrac{y^2}{76}- \dfrac{x^2}{324}=1

76

y

2

−

324

x

2

=1 .

7 0

3 years ago

Does the point (–3, 4) satisfy the equation y = –2x + 5? Yes Or No

Mekhanik [1.2K]

Answer:

No

Step-by-step explanation:

y = -2x + 5

4 = -2(-3) + 5 - Substitute both x and y

4 = 6 + 5 - Simplify

4 ≠ 11

Hence, no, (-3, 4) doesn't statify the equation y = -2x + 5

6 0

2 years ago

NO LINKS!! Explain your answers (show the support by showing the changes in x and y on your table). If the relationship is linea

sdas [7]

Answer:

<u>Linear relationship</u>: increasing or decreasing one variable will cause a corresponding increase or decrease in the other variable.

<u>Inverse relationship</u>: the value of one variable decreases as the value of the other variable increases.

<u>Exponential relationship</u>: a constant change in the independent variable (x) gives the same proportional change in the dependent variable (y)

<u>Question 5</u>

As the x-value increases (by one unit), the y-value decreases.

Therefore, this is an inverse relationship.

The y-values are calculated by dividing 35 by the x-value.

$\sf y=\dfrac{35}{x}$

**I believe there is a typing error in the table and that the y-value of x = 3 should be 11.67**

<u>Question 6</u>

As the x-value increases, the y-value increases. The y-value increases by a factor of 5 for each x-value increase of 1 unit.

Therefore, this is an exponential relationship.

$\sf y=5^x$

5 0

2 years ago

I’m confused on this one

Mandarinka [93]

Remark

If the lines are parallel then triangle RQS will be similar to triangle RTP

From that, all three lines in one triangle will bear the same ratio to all three lines of the second triangle.

Givens

PQ = 8

QR = 5

RS = 15

ST = x + 3

Ratio

QR/RP = RS/RT

Sub and solve

RP = 5 + 8

RP = 13

RT = 15 + x + 3

RT = 18 + x

5/13 = 15 / (18 + x) Cross multiply

5(18 + x) = 195 Remove the brackets on the left.

90 + 5x = 195 Subtract 90 from both sides.

5x = 105 Divide by 5

x = 105/5

x = 21 Answer <<<<<<<

3 0

3 years ago