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Alex73 [517]
3 years ago
10

Find the perimeter and area of following rectangle

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0
Perimeter:
3ab^2 + 3ab^2 + 5a^2b^4 + 5a^2b^4
= 6ab^2 + 10a^2b^4

Area:
3ab^2 x 5a^2b^4 = 15a^3b^6
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Which transformations will map octagon PQRSTVWZ onto itself?
Usimov [2.4K]

Answer:

Rotation, Reflection and Translation.

4 0
3 years ago
Whenever 2 line or intersect at 90 the 2 lines are said to be ?
Sedaia [141]
Two lines that intersect at 90 degrees are considered perpendicular to each other.

7 0
3 years ago
Read 2 more answers
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
2 years ago
Plz help with any of them it’s a emergency
devlian [24]
To find a perimeter, add all sides together:

9) 12 + 12 + 8 + 8 = 20 + 20 = 40 in
10)  3 + 3 + 3 + 3 = 6 + 6 = 12 cm

To find area, multiply length and width, or base and height:

11) 3 x 6 = 18 
12) 10 x 30 = 300 ft
13) 12 x 12 = 144 cm
14) 7 x 4 = 28 m

15) 
Perimeter: 2(2) + 2(16) = 4 + 32 = 36
Area: 1 x 16 = 16


hope this helps
7 0
3 years ago
Read 2 more answers
The figure shows the dimensions of a wall having a door and window of a room. Write an algebraic expression for the area of the
qwelly [4]

Answer:

Area of the wall to be painted = (11x² + 12x) square units

Step-by-step explanation:

The figure that should be attached to this question is missing. The figure was obtained and is attached to this solution provided.

From the image attached, it is given that the dimension of the rectangular wall to be painted is (4x+3) by (4x), the dimensions of the window is (2x) by (x) and the dimensions of the door is (x) by (3x).

Since, the window space and the door space cannot be painted along with the wall, the Area of the rectangular wall that will be painted will be given by the expression

(Total Area of the rectangular wall) - [(Area of window space) + (Area of door space)]

Area of a rectangular figure = Length × Breadth

Total area of rectangular wall = (4x+3) × 4x = (16x² + 12x) square units

Area of window space = (2x) × (x) = (2x²) square units

Area of door space = (x) × (3x) = (3x²) square units

Area of the wall to be painted = (16x² + 12x) - (2x² + 3x²)

= 16x² + 12x - 5x²

= (11x² + 12x) square units

Hope this Helps!!!

6 0
3 years ago
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