1 and 146
2 and 73
and that's about it
Answer:
1. 1350
2.2700
Step-by-step explanation:
probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
I think that it’s A) 2/5. I just multiplied the fractions with each other.
That would be : 6fg^3 + 5f^2g^2 + f^3g - 7....because there are no like terms