A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
C. I and II only
The absolute value has to be greater than negative q. And p must be greater than the absolute value of q.
Answer:
The range of this function is {-13, -1, 15}.
Step-by-step explanation:
Evaluate f(x) = 4x - 1 at {-3, 0, 4}:
f(-3) = -13
f(0) = -1
f(4) = 15
The range of this function is {-13, -1, 15}.
Answer:
A does not have any proportional relationship.
Step-by-step explanation:
All of the other tables have obvious relationships, leaving A to be the answer.
