1 km = 1000m
1 hr = 3600 s
189 km/h
189 * 1000 / 3600 m/s
189*5/18 m/s
945/18 m/s
315/6 m/s
105/2 m/s
52.5 m/s
in 10 s
52.5*10
525 m
Answer:
-3q² + 3qp + 2rp - 2rq + Sq - Sp
Step-by-step explanation:
first part
3q(p-q) = 3qp - 3q²
second part
2r(p-q) = 2rp - 2rq
third part
S(q-p) = Sq - Sp
then we put it all together
3qp - 3q² + 2rp - 2rq + Sq - Sp
in the right place possibly
-3q² + 3qp + 2rp - 2rq + Sq - Sp
The required range of the data is 24mm
The range of data is the difference between the largest value and the least value in a set of data.
Since we are not given the range of data. Let's assume we gave the following data:
34mm, 30mm, 20mm, 44mm, 31mm
From the data
Highest measurement = 44mm
Least measurement = 20mm
Find the range
Range = Highest measurement - Least measurement
Range = 44mm - 20mm
Range = 24mm
Hence the required range of data is 24mm
<em>NB: The concept can be applied to any set of data given for other measurements in (b) and (c)</em>
<em>Learn more here: brainly.com/question/1786006</em>
Answer:
y = -7x+34
Step-by-step explanation:
We have 2 points, so we can find the slope
m = (y2-y1)/(x2-x1)
= (6--1)/(4-5)
= (6+1)/(4-5)
= 7/-1
= -7
We can use point slope form to make an equation
y-y1 = m(x-x1)
y--1 = -7(x-5)
y+1 = -7(x-5)
Distribute
y+1 = -7x+35
Subtract 1 from each side
y+1-1 = -7x+35-1
y = -7x+34
