Please help me solve this problem!!

Match the sides based on their relationship to A PLEASE ANSWER ASAP

TiliK225 [7]

Answer:

13 hypotenuse

12 adjacent

5 opposite

5 0

3 years ago

Read 2 more answers

Y=x^2-6x+3 help write the vertex form of the equation

Artist 52 [7]

Answer:

$y=(x-3)^2-6$

Step-by-step explanation:

$y=x^2-6x+3$

This is written in the standard form of a quadratic function:

$y=ax^2+bx+c$

where:

ax² → quadratic term
bx → linear term
c → constant

You need to convert this to vertex form:

$y=a(x-h)^2+k$

where:

(h,k) → vertex

To find the vertex form, you need to find the vertex. For this, use the equation for axis of symmetry, since this line passes through the vertex:

$x=-\frac{b}{2a}$

Using your original equation, identify the a, b, and c terms:

$a=1\\\\b=-6\\\\c=3$

Insert the known values into the equation:

$x=-\frac{(-6)}{2(1)}$

Simplify. Two negatives make a positive:

$x=\frac{6}{2} =3$

X is equal to 3 (3,y). Insert the value of x into the standard form equation and solve for y:

$y=3^2-6(3)+3$

Simplify using PEMDAS:

$y=9-18+3\\\\y=-9+3\\\\y=-6$

The value of y is -6 (3,-6). Insert these values into the vertex form:

$(3_{h},-6_{k})\\\\y=a(x-3)^2+(-6)$

Insert the value of a and simplify:

$y=(x-3)^2-6$

:Done

6 0

2 years ago

The circle below is center Ed at O. Decide which length,if any, is definitely the same as the length. a) AD. b) BC. Justify your

Mars2501 [29]

Answer:

Point O is the center of the circle.

Part (a)

$\overline{A\:\!F}$ is a chord.

$\overline{OD}$ is a segment of the radius and is perpendicular to $\overline{A\:\!F}$

If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).

Therefore, $\overline{AD}=\overline{DF}$

Part (b)

If $\overline{BE}$ was extended past point E to touch the circumference it would be a chord.

As $\overline{OC}$ is perpendicular to $\overline{BE}$ , it would bisect the chord, but as $\overline{BE}$ is only a portion of a chord, $\overline{OC}$ does not bisect $\overline{BE}$ .

Therefore, there is no length equal to $\overline{BC}$ .

5 0

2 years ago

Which of the following is the graph of 2x+3y=6

Bond [772]

Taking point (0,-2) of graph one and replacing in the equation;

2x+3y=6

2(0)+3(-2)=6

-6=6

So graph isn't the required graph.

Taking point (0,2) of graph 2;

2x+3y=6

2(0)+3(2)=6

6=6

So, graph 2 is the required graph.

8 0

3 years ago

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You invest $2,500 in an account that grows 5% each year. what will be your investment amount after 6 years?

lesantik [10]

Answer: b. $3,374.65

Step-by-step explanation:

The exponential equation of growth (continuously) is given by :-

$y=Ae^{rx}$ , where A is the initial amount, r is the rate of growth ( in decimal) and x is the time period.

Given : You invest $2,500 in an account that grows 5% each year.

i.e. A= $2,500 and r= 5%=0.05

Then, the equation model this situation will be :-

$y=2500e^{0.05x}=2500(1.05)^x$

Now, At x= 6

$y=2500e^{0.05\times6}\\\\\Rightarrow\ y=2500e^{0.3}=3374.64701894\approx3374.65$

Hence, the investment amount after 6 years will be $3,374.65.

4 0

3 years ago