Jeremiah got $65 on birthday and spent some money on 3 video games and was left with $14.
He purchased 3 video games.
Let the cost one one video game be v.
The cost of each video game is same
So the cost of 3 video games is 3v.
Also he is left with $14 after paying for three games.
Hence
3v + 14 = 65
Subtracting 14 from both sides
3v + 14 -14 = 65-14
3v = 51
Dividing by 3 on both sides
v = 51/3
v = 17
Hence the cost of each video game is $17
The answer is D.) -2x^5y^3 + 4x^2y^2 + x^2
If you expand out the brackets you get this,
(4+5i)(a+2i) = 4a + (5a)i + 8i - 10
The -10 comes from 5i * 2i.
Squaring i becomes -1.
Let's group the real stuff together,
and imaginary separately,
(4a - 10) + (5a + 8)i
For this to be purely imaginary,
the real part needs to be zero.
Therefore 4a - 10 = 0
Solve for a.
7 2/3 + 8 5/6 = 16 1/2 ( or 32/2 )
Answer:
x<±1 and x< -3
Step-by-step explanation:
Given the inequality x^2-1/3x+9<0, we are to find the values of x that satisfies the inequality
x^2-1/3x+9<0
x^2-1/3x+9 (3x+9)²<0* (3x+9)²
(x^2-1)(3x+9) < 0
x²-1 < 0 and 3x + 9 <0
x²-1 < 0
x²<1
x<±√1
x<±1
Also 3x + 9 <0
3x < -9
x < -9/3
x < -3
Hence the required values of x are x<±1 and x< -3
