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masha68 [24]
3 years ago
9

Triangle JKL has an area of in2 and a perimeter of in.

Mathematics
1 answer:
S_A_V [24]3 years ago
5 0

Answer:

Area = 24 in²

Perimeter = 24in

Step-by-step explanation:

To find the area given the length of the 3 sides:

a= 8in

b= 6.4in + 3.6in= 10in

c= 6in

Add them together:

8in + 10in + 6in

= 24in²

To find the perimeter you do the same thing:

a= 8in

b= 10in

c= 6in

Add them together

=24in

DO <u>NOT</u> SQUARE THE ANSWER WHEN FINDING <u>PERIMETER</u>

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4 years ago
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astra-53 [7]

Answer:

Option: C is correct.

x=\ln\sqrt{\dfrac{t+1}{1-t}}

Step-by-step explanation:

We are asked to solve for 'x' such that we are given a equation as:

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This equation could also be written as:

e^x-e^{-x}=t(e^x+e^{-x})\\\\e^x-e^{-x}=te^x+te^{-x}\\\\e^x-te^x=te^{-x}+e^{-x}\\\\(1-t)e^x=(t+1)e^{-x}\\\\e^{2x}=\dfrac{t+1}{1-t}

on taking logarithmic function on both the sides we have:

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Hence, we have: x=\ln\sqrt{\dfrac{t+1}{1-t}}

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