1/6(12z-18)=2z-3
12/6z-18/6 =2z-3
2z-3=2z-3
there are infinite solutions for this equation or all real numbers
Here's the answer, using the quadratic formula
So the first integer is 61.
Then the others must be 62, 63, and 64. To check, you can add them all together. 61+62+63+64=250.
Answer:
8
Step-by-step explanation:
Sides AB and AC are equal
So,
3x - 5 = 7
+ 5 on both sides
3x = 12
divide both sides by 3
x = 4
Now take the 2x and plug in x for 4.
2(4) = 8
Final answer is 8.
