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2 years ago

12

Hello there a bot on here that puts a link to a virus it looks like this DONT DOWNLOAD IT ITS A VIRUS it could also get your ip

so use a vpn if you want to use it

1 answer:

I am Lyosha [343]2 years ago

8 0

Exactly. I'm seeing it everywhere now. Keep reporting them, and NEVERRR download

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Elisa sold 110 tickets for the football game. Adult tickets cost $2.50 and student tickets cost $1.10. If she collected $212, ho

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Is there answer choices

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3 years ago

The base parking charge at a mall on a Sunday is $2 per hour. If a vehicle is parked for 4 hours, only $6 is charged. What perce

chubhunter [2.5K]

2 dollars = 1 hour
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2 years ago

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Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

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2 years ago

100 POINTS!!!!!!

Andrews [41]

Answer:

A 4x2=7-15 X=

Step-by-step explanation:

B como dedos de los dedos de losdos para el desayuno

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2 years ago

Pls help question is on picture

NikAS [45]

Answer:

25 degrees

Step-by-step explanation:

5 * 5 = 25

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2 years ago

Read 2 more answers