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KonstantinChe [14]
3 years ago
15

One number is 6 more than twice another. If their sum is 51, find the numbers.

Mathematics
1 answer:
joja [24]3 years ago
7 0

Answer:

y=2x+6 ; x+y=51

Step-by-step explanation:

assuming x is one number and y is the other -

one number (y) is 6 more (+6) than twice another (2x) -

using that knowledge we form an equation -

y=2x+6

the sum (x+y) is 51

using this knowledge we can make the equation -

x+y=51

now you have -

y=2x+6 or 2x-y=-6

x+y=51

using system of equations -

you add the equations -

3x=45

x=15

y=51-x => y=36

hope this helps!!

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2x + 6

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3 years ago
Xander needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.
Aleksandr [31]

Answer:

c ≥ 56   is the REQUIRED INEQUALITY.

Step-by-step explanation:

Here, the given  question is INCOMPLETE.

Xander needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items. Choose the inequality and solution to represent the number of cans, c, that Xander must still collect.

Now, here:

The number of cans Xander needed to collect = At least 120

The number of items already collected =  64

c: the number of cans, c, that Xander must still collect.

Now, the number of cans to be collected  - Cans already collected  

=  120 - 64  = 56

So, the number of can he must collect to make a TOTAL OF AT LEAST 120 cans  =  56 cans

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3 0
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What is the value of f ( − 3a ), if f ( x ) = 2x 2 + 4x ?
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=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

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