Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
Correlation Coefficient (r) = 0.989
alph=0.05
Number of observations (n) = 8
determine if there is a linear correlation between chest size and weight.
Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.
What proportion of the variation in weight can be explained by the linear relationship between weight and chest size?
To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.
r^2 = square of the correlation Coefficient
r^2 = 0.989^2 = 0.978121
Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.
Answer:
Step-by-step explanation:
If your last value in your data is 80 then i think your answer would be 478.4725
Answer:
Phrases 2 and 4.
Step-by-step explanation:
6.5x+1.5<21
The sum of 1.5 and the product of 6.5 and a number is no greater than 21.
The product of 6.5 and a number, when increased by 1.5 is at most 21.
HOPE IT HELPS
(FROM CROSS)
Answer:
5x - y = 10x + 3y = 4
5x - y = 4..... 1
10x + 3y = 4.....2
multiply by -2 in eq 1 in both sides
-10x + 2y = -8
10x +3y = 4
eliminate one variable by adding the equations
5y = -4
y = - 4/5
sub the value of y in..1
5x - y = 4
5x + 4/5 = 4
5x = 16/5
divide by 5 on both sides
x = 16/25
(x ; y)
(16/25 ; -4/5)
