Question

Need help once again

Answer 1

Hi there!

$\large\boxed{\text{ She is incorrect.}}$

The format of a logarithmic equation is:

$a^{b} = c\\\\log_{a}c = b$

In this instance:

a = e

b = 3x

c = 7

Rewrite as the logarithmic equation:

$log_{e}7 = 3x$

Solve. Evaluate $log_{e}7$ and use algebra to find x:

$1.946 = 3x\\\\x = 0.649$