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tatuchka [14]
3 years ago
5

8c 2– c + 3 + 2c 2– c + 2

Mathematics
2 answers:
Sauron [17]3 years ago
8 0

Answer:

First, let me rewrite the problem as I see it:

Step-by-step explanation:

8c(2) - c + 3 + 2(c + 2) - c + 2

=

16c + 9

Pavel [41]3 years ago
4 0

Answer:

10 c to the second power -2c+5

Step-by-step explanation:

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Answer:

Step-by-step explanation:

you change it to an improper fraction for example 20 2/6x6 3/6

you gotta multiply the 6 in the 20 2/6 by 20 then add the 2 so it would be 122/6 do the same for the other and then you have 39/6 then multiply 122/6x39/6

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Look at the figure. Name the postulate or theorem you can use to prove the train goes congruent?
Nikolay [14]

Let us recall parallelogram properties, which states that opposite angles of parallelogram are congruent.

We can see from graph that side US is parallel to TR and measure of angle U equals to measure of angle R, therefore, quadrilateral drawn in our given graph is a parallelogram.

Since we know that opposite sides of parallelogram are congruent. In our parallelogram UT=SR and US=TR.

In our triangle STU and triangle TSR side TS=TS by reflexive property of congruence.

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4 years ago
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Please help me!!! (Don't joke or banned)
olasank [31]

<u>Answer:</u>

<h2>P = $100.80</h2>

<u>Steps:</u>

  • Price after clearance:

Pc = 120 - (120/100×20)

Pc = 120 - (1.2×20)

Pc = 120 - 24

Pc = 96

  • Price after sales tax:

P = Pc + (Pc/100×5)

P = 96 + (96/100×5)

P = 96 + (0.96×5)

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3 0
3 years ago
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A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?
AlekseyPX

Answer:

The width of the sandbox is 42\frac{2}{3} \ ft.

Step-by-step explanation:

Given,

Area of the sandbox = 10\frac{2}{3}=\frac{32}{3}\ ft^2

Length = \frac{1}{4}\ ft

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

Area = Length\times Width

On substituting the given values, we get;

\frac{1}{4}\times w=\frac{32}{3}\\

By cross multiplication method, we get;

w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft

Hence The width of the sandbox is 42\frac{2}{3} \ ft.

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