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3 years ago

Determine the equation of the line with a slope of m = 2 and the point (-2, 1). Write your answer in slope-

Mathematics

1 answer:

prohojiy [21]3 years ago

5 0

Answer:

Step-by-step explanation:

y - 1 = 2(x + 2)

y - 1 = 2x + 4

y = 2x + 5

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Evaluate the polynomial 6x - y for x = 3 and y =4

Mashcka [7]

6 x 3 is 18. y is equal to 4. 18 minus 4 is 14. The answer is 14.

8 0

3 years ago

If a=3 and b=4 wat is it ?

Anarel [89]

Answer:

what is what?

Step-by-step explanation:

5 0

2 years ago

Find the coordinates of the midpoint of line AB given the coordinates: A(-1, 5) B(2,-3)*

Naily [24]

Answer:

$\bold{M_{AB}\left(\frac12\,,\ 1\right)}$

Step-by-step explanation:

The midpoint of AB coordinates are: $M_{AB}\left(x_M\,,\ y_M\right)$ where:

$x_M=\frac{x_A+x_B}2=\frac{-1+2}2=\frac12\\\\y_M=\frac{y_A+y_B}2=\frac{5+(-3)}2=\frac{2}2=1$

6 0

3 years ago

Simplify6(x - 3) = -42.

Alinara [238K]

Answer:

x = -4

Step-by-step explanation:

First Expand :

6(x - 3)

= 6x - 18

Now you need to Simplify:

6x - 18 = -42

And now get the 6x by itself by doing this :

6x - 18 = -42

+18 +18

= > 6x = -24

And 6 x 4 = 24

But 6 x -4 = -24

So :

6x/6 and -24/6

= >> x = -4

7 0

2 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.)

gavmur [86]

Answer:

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{x^2+y^2+49}+7\right)=14$

Step-by-step explanation:

to find the limit:

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\dfrac{x^2+y^2}{\sqrt{x^2+y^2+49}-7}\right)$

we need to first rationalize our expression.

$\dfrac{x^2+y^2}{\sqrt{x^2+y^2+49}-7}\left(\dfrac{\sqrt{x^2+y^2+49}+7}{\sqrt{x^2+y^2+49}+7}\right)$

$\dfrac{(x^2+y^2)(\sqrt{x^2+y^2+49}+7)}{(\sqrt{x^2+y^2+49}\,)^2-7^2}$

$\dfrac{(x^2+y^2)(\sqrt{x^2+y^2+49}+7)}{(x^2+y^2)}$

$\sqrt{x^2+y^2+49}+7$

Now this is our simplified expression, we can use our limit now.

$\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{x^2+y^2+49}+7\right)\\\sqrt{0^2+0^2+49+7}\\7+7\\14$

Limit exists and it is 14 at (0,0)

4 0

3 years ago