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Verizon [17]
2 years ago
13

Consider the rates 45 mile in 8 minutes and 4 minutes to travel 25 mile. Select the statement(s) that are true. Multiple select

question. Cross out A) The rate 45 mile in 8 minutes has a unit rate of 10 miles per minute. Cross out B) The rate 45 mile in 8 minutes has a unit rate of 110 mile per minute. Cross out C) The rate 4 minutes to travel 25 mile has a unit rate of 10 minutes per mile. Cross out D) The rate 4 minutes to travel 25 mile has a unit rate of 110 minute per mile. Cross out E) Both rates are equivalent. Cross out F) The rates are not equivalent.
Mathematics
1 answer:
icang [17]2 years ago
7 0

Answer:

F) The rates are not equivalent.

Step-by-step explanation:

Consider the rates 45 mile in 8 minutes and 4 minutes to travel 25 mile. Select the statement(s) that are true. Multiple select question.

We find the unit rates

a) 45 mile in 8 minutes , we find the unit rate in miles per minute

8 minutes = 45 miles

1 minute = x

8 × x = 45 miles × 1 minute

x = 45 miles/8 minutes

x = 5.625 miles/ minute

b) 4 minutes to travel 25 miles. Find the unit rate is minutes per mile

25 miles = 4 minutes

1 mile = x

25miles × x = 4 minutes × 1

x = 4 minutes/25 miles

x = 0.16 minutes/mile

Hence, the correct option is

F) The rates are not equivalent.

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saveliy_v [14]

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B. D (-4, 3)

Step-by-step explanation:

In quadrant II x value is -ve and y value is positive.

7 0
2 years ago
How much does a customer pay for an article marked at $50 if a sales tax of 6% is charged?
Brrunno [24]

Answer:

53$

Step-by-step explanation:

6% of 50 is 3, 50+3=53

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2 years ago
What's the ordered pair for point H in the graph above?
Bumek [7]

Answer:

C) (5,0)

Step-by-step explanation:

1. The correct answer is C) because when we move five units to right from the origin, and zero units up, we end up at point H!

6 0
2 years ago
Product FIFO LIFO
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Answer:

The null hypo would be the difference is greater than 0

so the alternate hypothesis would be less than or equal to 0

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8 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
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