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polet [3.4K]
3 years ago
5

Which sets of numbers are closed under subtraction?

Mathematics
2 answers:
nignag [31]3 years ago
4 0
C. Is your correct answer
stealth61 [152]3 years ago
3 0
Integers are closed under subtraction.

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An amount of 1,500.00 is deposited in a bank paying an annual interest rate of 4.3% compounded quarterly. What is the balance af
defon

First, multiply the 1,500 by 4.3% to come up with $64.50 every three months (the question says compounded quarterly).

$64.50 x 4(quarters in a year) = $258.00 per year

$258.00 x 6 years = $1,548.00

$1,500.00 + $1,548.00 = $3,048.00 balance after six years


8 0
3 years ago
Evaluate: 2·5\4^-2 <br> A) 5\8 B<br> B) 8\5 <br> C) 40 <br> D) 160
alexandr402 [8]
D. 160 you simplify the expression to get your answer.
3 0
3 years ago
Read 2 more answers
Fator the following problem x^2+12x+36​
Mekhanik [1.2K]

Answer:

(x-6)^2

Step-by-step explanation:

Hope this helped

5 0
3 years ago
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-2 (4x-9) = -18 ×=___​
Dahasolnce [82]

Answer:

x = 9/2 or 4 1/2 or 4.5

Step-by-step explanation:

Divide both sides by the numeric factor on the left side, then solve. Hope this helped :)!

5 0
3 years ago
A number cube has faces numbered 1 through 6, and a coin has two sides, "heads" and "tails". The
Mama L [17]

Answer:

The <em>required probability</em> is \dfrac{1}{12}.

Step-by-step explanation:

Let <em>A </em>be the event of rolling the number cube.

Let <em>B</em> be the event of tossing the coin.

Total number of possibilities of rolling the number cube and tossing the coin are <em>12 </em>here.

\{(1,H),(2,H),(3,H),(4,H),(5,H),(6,H),(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)\}

where <em>H</em> means Head on toss of coin and <em>T</em> means Tails on toss of coin.

Formula for probability of an event <em>E</em> is:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Here, we have to find the probability of event 'E' i.e. getting a 6 on number cube and heads on coin.

Number of favorable cases are <em>1 </em>and total cases are <em>12</em>.

\Rightarrow P(E) = \dfrac{1}{12}

6 0
3 years ago
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