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uysha [10]
3 years ago
13

Simplify 3(x+2)-5x1. 6-2x2. 8x+23.-2x+24.2x+6​

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0

Answer:

-2x+6

Step-by-step explanation:

first multiply the 3(x+2)

that equals 3x+6-5x

Add like terms

-2x+6

gulaghasi [49]3 years ago
7 0

Answer:

-2x + 6

Step-by-step explanation:

Step 1: Write expression

3(x + 2) - 5x

Step 2: Distribute

3x + 6 - 5x

Step 3: Combine like terms

-2x + 6

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earnstyle [38]
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  • BC = 8 units
  • perimeter = 2(l+b) = 2(8+4) = 2(12) = 24 units

hope it helps...!!!

3 0
2 years ago
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Consider the following system:
Goryan [66]
You did not include the choices. However, I answered one that just included them. I've included the possible answers below and then the correct answers. 

<span>A multiple of Equation 1. 
B. The sum of Equation 1 and Equation 2 
C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2. 
D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2. 
E. The sum of a multiple of Equation 1 and Equation 2.

</span>A, B and E.

Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D. 
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3 years ago
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I need help completing this answer are you available
melomori [17]

Answer:

Step-by-step explanation:

7 0
2 years ago
Which equation is y = 9x2 + 9x – 1 rewritten in vertex form?
Anastasy [175]

Answer:

y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

Step-by-step explanation:

An equation in the vertex form is written as

y = a (x-h) + k

Where the point (h, k) is the vertex of the equation.

 

For an equation in the form ax ^ 2 + bx + c the x coordinate of the vertex is defined as

x = -\frac{b}{2a}

In this case we have the equation y = 9x^2 + 9x - 1.

Where

a = 9\\\\b = 9\\\\c = -1

Then the x coordinate of the vertex is:

x = -\frac{9}{2(9)}\\\\x = -\frac{9}{18}\\\\x = -\frac{1}{2}

The y coordinate of the vertex is replacing the value of x = -\frac{1}{2} in the function

y = 9 (-0.5) ^ 2 + 9 (-0.5) -1\\\\y = -\frac{13}{4}

Then the vertex is:

(-\frac{1}{2}, -\frac{13}{4})

Therefore The encuacion excrita in the form of vertice is:

y = a(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

To find the coefficient a we substitute a point that belongs to the function y = 9x^2 + 9x - 1

The point (0, -1) belongs to the function. Thus.

-1 = a(0 + \frac{1}{2}) ^ 2 -\frac{13}{4}

-1 = a(\frac{1}{4}) -\frac{13}{4}\\\\a = \frac{-1 +\frac{13}{4}}{\frac{1}{4}}\\\\a = 9

<em>Then the written function in the form of vertice is</em>

y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}

7 0
3 years ago
Write an equation in standard form for the line that has undefined slope and passes through (-6, 4)
Nikitich [7]

Answer:

y = ix + 6i + 4

Step-by-step explanation:

Since the line has undefined slope or indefinite slope we connote that the slope is (i)

Slope(m) of straight line = change in y ÷ change in x

Taking another  point (x,y) on the line:

i = \frac{y - 4}{x - -6}

i = \frac{y - 4}{x + 6}

Cross multiplying gives;

y - 4 = ix + 6i

y = ix + 6i + 4

6 0
3 years ago
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