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3 years ago

13

Simplify 3(x+2)-5x1. 6-2x2. 8x+23.-2x+24.2x+6

2 answers:

chubhunter [2.5K]3 years ago

8 0

Answer:

-2x+6

Step-by-step explanation:

first multiply the 3(x+2)

that equals 3x+6-5x

Add like terms

-2x+6

gulaghasi [49]3 years ago

7 0

Answer:

-2x + 6

Step-by-step explanation:

Step 1: Write expression

3(x + 2) - 5x

Step 2: Distribute

3x + 6 - 5x

Step 3: Combine like terms

-2x + 6

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What is the length of (AB)?

earnstyle [38]

AB = 4 units
BC = 8 units
perimeter = 2(l+b) = 2(8+4) = 2(12) = 24 units

hope it helps...!!!

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2 years ago

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Consider the following system:

Goryan [66]

You did not include the choices. However, I answered one that just included them. I've included the possible answers below and then the correct answers.

<span>A multiple of Equation 1.
B. The sum of Equation 1 and Equation 2
C. An equation that replaces only the coefficient of x with the sum of the coefficients of x in Equation 1 and Equation 2.
D. An equation that replaces only the coefficient of y with the sum of the coefficients of y in Equation 1 and Equation 2.
E. The sum of a multiple of Equation 1 and Equation 2.

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Adding and multiplying the terms allow them to keep working. However, you must make sure that each variable is changed each time. Not just one as in C and D.

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3 years ago

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I need help completing this answer are you available

melomori [17]

Answer:

Step-by-step explanation:

7 0

2 years ago

Which equation is y = 9x2 + 9x – 1 rewritten in vertex form?

Anastasy [175]

Answer:

$y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}$

Step-by-step explanation:

An equation in the vertex form is written as

$y = a (x-h) + k$

Where the point (h, k) is the vertex of the equation.

For an equation in the form $ax ^ 2 + bx + c$ the x coordinate of the vertex is defined as

$x = -\frac{b}{2a}$

In this case we have the equation $y = 9x^2 + 9x - 1$ .

Where

$a = 9\\\\b = 9\\\\c = -1$

Then the x coordinate of the vertex is:

$x = -\frac{9}{2(9)}\\\\x = -\frac{9}{18}\\\\x = -\frac{1}{2}$

The y coordinate of the vertex is replacing the value of $x = -\frac{1}{2}$ in the function

$y = 9 (-0.5) ^ 2 + 9 (-0.5) -1\\\\y = -\frac{13}{4}$

Then the vertex is:

$(-\frac{1}{2}, -\frac{13}{4})$

Therefore The encuacion excrita in the form of vertice is:

$y = a(x +\frac{1}{2}) ^ 2 -\frac{13}{4}$

To find the coefficient a we substitute a point that belongs to the function $y = 9x^2 + 9x - 1$

The point (0, -1) belongs to the function. Thus.

$-1 = a(0 + \frac{1}{2}) ^ 2 -\frac{13}{4}$

$-1 = a(\frac{1}{4}) -\frac{13}{4}\\\\a = \frac{-1 +\frac{13}{4}}{\frac{1}{4}}\\\\a = 9$

<em>Then the written function in the form of vertice is</em>

$y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}$

7 0

3 years ago

Write an equation in standard form for the line that has undefined slope and passes through (-6, 4)

Nikitich [7]

Answer:

y = ix + 6i + 4

Step-by-step explanation:

Since the line has undefined slope or indefinite slope we connote that the slope is (i)

Slope(m) of straight line = change in y ÷ change in x

Taking another point (x,y) on the line:

i = $\frac{y - 4}{x - -6}$

i = $\frac{y - 4}{x + 6}$

Cross multiplying gives;

y - 4 = ix + 6i

y = ix + 6i + 4

6 0

3 years ago