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PSYCHO15rus [73]
3 years ago
15

Most of the earth surface is covered with

Chemistry
1 answer:
Liula [17]3 years ago
4 0
I believe it is salt water
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(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW
Aleonysh [2.5K]

Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = <em>2.3x10⁻³M  InF₃. </em>Thus:

[In⁺³] = 2.3x10⁻³M  InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M  In⁺³

[F⁻] = 2.3x10⁻³M  InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M  In⁺³] × [7.0x10⁻³M F⁻]³ = <em>7.9x10⁻¹⁰</em>

<em></em>

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, <em>solubility is 6.31x10⁻⁶M</em>

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4 years ago
Without constants you would not know which variable affected the
bonufazy [111]
Two independent variables could change at the same time, and you would not know which variable affected the dependent variable
4 0
3 years ago
Define electron affinity
LekaFEV [45]
Electron affinity corresponds to the energy released when an electron is added to<span> a </span>neutral atom in the gas phase<span>.

hope this helps!</span>
8 0
3 years ago
If a recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb what volume in liters
Bad White [126]

The volume in liters of 3245 aluminum cans is 24.8 L.

A recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb. The mass of 3245 aluminum cans is:

3245 cans \times \frac{1lb}{22cans} = 147.5 lb

To convert mass to volume, we need the density of aluminum (5.95 lb/L). The volume corresponding to 147.5 lb of aluminum is:

147.5 lb \times \frac{1L}{5.95 lb} = 24.8 L

The volume in liters of 3245 aluminum cans is 24.8 L.

You  can learn more about density here: brainly.com/question/1841285

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The control rods are made of what materials
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