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Ivanshal [37]
4 years ago
12

The physical and chemical properties of a molecule depend on its structure. Here are two ball-and-stick models for two compounds

that have the same molecular formula but different structures and different chemical properties.

Chemistry
2 answers:
djyliett [7]4 years ago
7 0

Answer:

Ethanol has covalent intramolecular bonds. Ethanol is polar. Ethanol has dispersion intermolecular forces. Dimethyl ether is polar. Dimethyl ether forms hydrogen bonds. Dimethyl ether has dispersion intermolecular forces.

Explanation:

Ethanol is not a carboxylic acid. It is an alcohol and it has covelent intramolecular bonds. It is polar and it also has dispersion intermolecular forces.

Dimethyl ether is also polar and it has forms hydrogen bonds. It also has dispersion intermolecular forces. Dimethyl ether does not have ionic intramolecular forces

arlik [135]4 years ago
4 0

Answer:

<u>Isomerism:</u>

"The different compounds having the same chemical composition or molecular structure. But, there physical properties vary in many ways,i.e boiling point, melting points etc. As there atoms or molecules are arranged in different patterns."

The two compounds are then called as the isomers, as they share the same chemical properties between them but they have different physical properties.

<u>For example: </u>

We have ethanol and Di-methyl ether, as both the compounds acts as the isomers for each other due to difference in the arrangement of the molecules or atoms.

Explanation:

<u>Ethanol and Di-methyl ether:</u>

  1. Ethanol has different arrangement or pattern of atoms in its structure. As the bonding on the intra-molecular level inside the ethanol structure is the covalent bonding( As it involves sharing of a pair of electrons between the different atoms). Due, to the covalent bonding between the two or more atoms there is a difference in polarity of the compound's structure. As this polarity pattern of the compound results in its polar nature.
  2. For the Di-methyl ether the hydrogen bonding is present and it makes the compound more different from the rest of the compounds. As it too has the polar nature, but due to the hydrogen bonding between the atoms or the molecules of the compound.

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8 0
3 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (<em>M)</em> is calculated from the following equation:

<em>M</em> = <em>n</em> ÷ <em>V</em>

where <em>n</em> is the number of moles of the solute in the solution, and <em>V</em> is the volume of the solution.

Accordingly, the number of moles of the solute is given by

<em>n</em> = <em>M</em> x <em>V</em>

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

<em>n </em>(1) = <em>M </em>(1) x <em>V </em>(1)

<em>n </em>(2) = <em>M </em>(2) x <em>V </em>(2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

<em>n</em> (1) = <em>n</em> (2)

and

<em>M</em> (1) x <em>V</em> (1)<em> </em>= <em>M</em> (2) x <em>V</em> (2)

For the stock solution, <em>M</em> (1) = 1.244 M, and <em>V</em> (1) is the volume needed. For the dilute solution, <em>M</em> (2) = 0,1281 M, and <em>V</em> (2) = 250.0 mL.

The volume of the stock solution needed, <em>V</em> (1), is calculated as follows:

<em>V</em> (1) = <em>M</em> (2) x <em>V</em> (2) ÷ <em>M</em> (1)

<em>V</em> (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

<em>V </em>(1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

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