Answer:
option b
Step-by-step explanation:
x = -3 (Not possible)
x = 5
So, x = 5
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We have been given that a cosine function is a reflection of its parent function over the x-axis. The amplitude of the function is 11, the vertical shift is 9 units down, and the period of the function is . The graph of the function does not show a phase shift. We are asked to write the equation of our function.
We know that general form a cosine function is , where,
A = Amplitude,
= Period,
c = Horizontal shift,
d = Vertical shift.
The equation of parent cosine function is . Since function is reflected about x-axis, so our function will be
.
Let us find the value of b.
Upon substituting our given values in general cosine function, we will get:
Therefore, our required function would be .
Answer:
∠MSR is right angle
Step-by-step explanation:
It is given that RHOM is a Rhombus
Also ΔHOM, ΔMHR, ΔRHO and ΔOMR are isosceles triangles
Let us take ΔMSR and ΔRSH
∠MRS =∠HRS ( since it is given that the diagonal RO bisects ∠R)
∠RMS =∠RHS ( since Δ MRH is isosceles triangle )
RS = RS ( common side )
By AAS congruency rule ΔMSR ≅ ΔHSR
so we have
∠MSR=∠RSH ( corresponding parts of congruent triangles are congruent)
also we have
∠MSR +∠RSH =180° ( supplementary angles)
∠MSR +∠MSR=180° ( since ∠MSR=∠RSH)
2∠MSR= 180°
∠MSR =90°
Hence ∠MSR is right angle
