Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so 
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So
Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Answer:
It will take her 4 1/3 hours
Step-by-step explanation: so you know you needed to add 4 and 1/3 and you turn the 4 into 4/1 and 1/3 and since it adding you have to have the same denominator and you multiply 1x3 and if you do it on the bottom you have to do it on top so you also do 4x3 and 4x3 is 12 and one 1x3 is 3 and so you don't have to have to do it on the other fraction because now they have the same denominator now and now you add 12/3 + 1/3 and you shall get 13/3 and then you divide 13 divided by 3 and you shall get 4 1/3 and that shall be your answer.
hope it helps you!
Answer is below..............
X= 1 y=4, x=2 y=8, x=3 y=12
Answer:
D. 15.7 yards
Step-by-step explanation:
The safety rail makes a curved side of a quarter circle.
The length of the safety rail = circumference of the curved part only of a quarter circle = ¼*2πr
Where,
radius = 10 yards
π = 3.14
Plug in the values
= ¼*2*3.14*10
= 15.7 yards.
✅The rail is 15.7 yards long.
