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777dan777 [17]
2 years ago
12

Peter wants to make for necklaces that are the same way. He asked his friends to cut the string for the necklace is 15 paper cli

ps long. With all the links me the same explain your think
Mathematics
1 answer:
postnew [5]2 years ago
5 0

Correct question is;

Peter wants to make four necklaces that are the same way. He asked his friends to cut the string for the necklace 15 paper clips long. Would all the lengths be the same? Explain your think

Answer:

No, the lengths would not be the same. This is due to the fact the the paper clips could be in different sizes.

Step-by-step explanation:

We are told that he wants to make four necklaces that are the same way and that he told his friends to cut the string for the necklace 15 paper clips long.

Now, we are not told the sizes of the paper clips and we know that paper clips come in different sizes. Thus the paper clips in which the strings are cut could be in different sizes. Therefore, the lengths wouldn't be the same due to that.

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There correct answer is B!
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A table showing pairs of r- and yvalues is shown below.
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Answer:

4

Step-by-step explanation:

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Write the expression in complete factored form<br><br> 4u^2(a-3)+q(a-3)
Sauron [17]

[ Answer ]

\boxed{\bold{4au^{2} \ - \ 12u^{2} \ + \ aq \ - \ 3q}}

[ Explanation ]

  • Factor: 4u^{2}(a - 3) + q(a - 3)

-------------------------------------

  • Expand 4u^2\left(a-3\right): 4au^2-12u^2

4au^2-12u^2+q\left(a-3\right)

  • Expand

q\left(a-3\right): aq-3q

  • Answer

4au^2-12u^2+aq-3q

\boxed{\bold{[] \ Eclipsed \ []}}

3 0
2 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
A student ticket for a high school basketball game costs $3.00. A monthly game pass costs $20.00. Which inequality represents th
Nana76 [90]
3x greater than or equal to 20
3x = 20
X= 7 games for the pass to be better
3(7)=21
4 0
2 years ago
Read 2 more answers
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