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Travka [436]
3 years ago
9

6. Three bunches of flowers can be bought for $9.48. Four bunches can be bought for $10.64. Which is the better buy?​

Mathematics
1 answer:
lawyer [7]3 years ago
5 0
The better buy would be four bunches for $10.66 because each bunch of flowers would be $2.66 compared to $3.16 per bunch.
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What is the compounded interest if $410 is invested for 10 years at 8% compounded continuously
tatiyna
\bf \textit{Continuous Compounding Amount}\\\\
A=Pe^{rt}\qquad \begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$410\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
t=years\to &10
\end{cases}

so, that gives you  the compounded amount, after 10 years, if you want to know how much interest was earned? well, just subtract the Principal from the Amount, or A - P  <--- that's how much interest was earned
4 0
3 years ago
Read 2 more answers
Find the equation of the line through point (5,1) and perpendicular to 5x−y=−3. Use a forward slash (i.e. "/") for fractions (e.
IRINA_888 [86]
Y = -1/5x + 2

A line perpendicular to another line has an opposite reciprocal slope. What opposite means is that you flip the sign (from - to + or from + to -) and reciprocal means that you flip the numerator and denominator (so if line A is perpendicular to line B and line As slope is -3, line Bs slope would be 1/3).

First find the slope of 5x - y = -3
Add y to both sides
5x = y - 3
Add 3 to both sides
y = 5x + 3

So the slope of the line is 5. That means the slope of of the perpendicular line is -1/5.

Plug the slope of the perpendicular line and the point (5, 1) into point slope form to solve the equation

y - y1 = m(x - x1)
y - 1 = -1/5(x - 5)
y - 1 = -1/5x + 1
y = -1/5x + 2
3 0
2 years ago
Select all of the names of this polygon
babunello [35]

Answer: i believe its rhombus rectangle quadrilateral


Step-by-step explanation:


4 0
3 years ago
Triangle abc is such that ab=4 and ac=8 if m is the midpoint of bc and am=3, what is the length of bc?
zavuch27 [327]
This is an interesting question. I chose to tackle it using the Law of Cosines.
  AC² = AB² + BC² - 2·AB·BC·cos(B)
  AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
  AC² - 2·AM² = -AB² + BC² - 2·MB²

We know that MB = BC/2. When we substitute the given information, we have
  8² - 2·3² = -4² + BC² - BC²/2
  124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
  2√31 = BC ≈ 11.1355

4 0
3 years ago
According to a 2018 survey by Bankrate, 20% of adults in the United States save nothing for retirement (CNBC website). Suppose t
nalin [4]

Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of adults in the United States save nothing for retirement (CNBC website).

This means that p = 0.2

Suppose that sixteen adults in the United States are selected randomly.

This means that n = 16

What is the probability that three or less of the selected adults have saved nothing for retirement?

This is:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{16,0}.(0.2)^{0}.(0.8)^{16} = 0.0281

P(X = 1) = C_{16,1}.(0.2)^{1}.(0.8)^{15} = 0.1126

P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.2111

P(X = 3) = C_{16,3}.(0.2)^{3}.(0.8)^{13} = 0.2463

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0281 + 0.1126 + 0.2111 + 0.2463 = 0.5981

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

4 0
3 years ago
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