All categories

2 years ago

6. Three bunches of flowers can be bought for $9.48. Four bunches can be bought for $10.64. Which is the better buy?

1 answer:

5 0

The better buy would be four bunches for $10.66 because each bunch of flowers would be $2.66 compared to $3.16 per bunch.

You might be interested in

What is the common ratio of 2, 10/3, 50/9

mojhsa [17]

The common ratio of 2, 10/3, 50/9 is $\frac{10}{6}$

<u>Solution:</u>

Given, series of elements are $2, \frac{10}{3}, \frac{50}{9}$

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take $\frac{10}{3}$ and 2

$\text { Then, common ratio }=\frac{\frac{10}{3}}{2}$

$\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}$

Hence, the common ratio of the given series is $\frac{10}{6}$

6 0

3 years ago

If Z is the midpoint of RT, what are x, RZ, and RT?

oksian1 [2.3K]

Option C is the answer to your question!!!

7 0

3 years ago

Read 2 more answers

Trains on the Glasgow Subway depart every 4 minutes, and a complete circuit takes 24 minutes. Ewan sets off at 8.30 am on a trai

Stolb23 [73]

Trains depart after every 4 minutes.
Total time train takes to complete a circuit= 24 minutes
Evan sets off at 8:30 am, so he will be back at 8:54 am.
So time of trains coming in opposite direction:
8: 34 am
8:38 am
8:42 am
8:46 am
and 8:50 am
5 trains coming in opposite directions.
Now the trains started at 8:06 am from the stations are:
8:06 am
8:10 am
8:14 am
8:18 am
8:22 am
and 8:26 am.
So there are 6 trains started the circuit at 8:06 am.

Now total number of trains=6+5=11 trains

Answer: 11 trains will pass on complete circuit.

7 0

3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

5 0

3 years ago

Help&EXPLAIN <br><br> Don’t use for points or will be reported and I’ll take the points back

ella [17]

Answer:

x = 60°

Step-by-step explanation:

since, the triangles are complementary the sum of their measures will be 90°

now,

=》30° + x = 90°

=》x = 90° - 30°

=》x = 60°

4 0

2 years ago

6. Three bunches of flowers can be bought for $9.48. Four bunches can be bought for $10.64. Which is the better buy?​

6. Three bunches of flowers can be bought for $9.48. Four bunches can be bought for $10.64. Which is the better buy?