suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
To find the volume of a cylinder , you will use the formula
V = Bh, where B is the area of the circular base.
Pi x r^2 x h
pi x 6^2 x 12
V = 432
The volume of the cylinder is 432pi cm³.
It is as 5x's as much.
<em>$0.30 X 5 = $1.50</em>
Hope I helped
Answer:
2,340,208.5 or 2,340,209
Step-by-step explanation:
You could answer this by multiplying the current population of 800,000 by 1.05 (1.05 represents the annual growth rate of population) and do that 22 times. But that would take a while.
we got 1.05 because the formula says that y = a( 1 + r ) power t
for a we will give it 1
so y = 1 ( 1 + 0.05) power t
it will give us 1.05
to do this faster, you would first calculate (1.05)22and then multiply this by 800,000.
So, 800,000 x (1.05)22 = 2,340,208.5 or 2,340,209
Answer:
gas it's gas
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