Answer:
i got -8 but the closest is -7 so u can tried that
Step-by-step explanation:
We know
in the graph two points
point 1 (2,1) and point 2 (-1,-4)
the equation in point-slope form is ----------------> (y-y1)=m(x-x1)
step 1
find the value of m
m=(y2-y1)/(x2-x1)----------> (-4-1)/(-1-2)--------> m=5/3
step 2
with the point (-1,-4) and m=5/3
find the equation in point-slope form
(y-(-4))=(5/3)*(x-(-1))-------------> (y+4)=(5/3)(x+1)
the answer is the option d) ( y+ 4 ) =+ 5/3 ( x + 1 )
C can be found using pythagoras theorem. c2=a2+b2. Now, b is not given, but we know that cos(theta)=b/c=>b=c*cos(theta). Substituting b in the above relation, c2=a2+c2(cos(theta))^2=>c2=a2/(1-cos((theta))^2). c is the squareroot of c2. Hence c=sqrt(2/(1-cos((theta))^2))
A linear equation is an equation for a straight line. And yes that is a linear equation. Because<span> it is of the form
h(x) = mx + b
where m=0 and b = 23
h(x) = mx + 23</span>
