Answer:
25%
Step-by-step explanation:
Probability = # of favorable outcomes / possible outcomes
favorable outcomes is what we want to happen ( throwing more than 3 pitches )
So to find the # of favorable outcomes we must find the frequency that the pitcher throws more than 3 pitches ( note: frequency of throwing 3 pitches is not included)
There are two possible outcomes of the pitcher pitching more than 3 pitches, 4 pitches having a frequency of 15, and 5 pitches which has a frequency of 10
So # of favorable outcomes = 10 + 15 = 25
Now we want to find the # of possible outcomes.
To do so we simply add the frequencies of each possible outcome.
15 + 20 + 40 + 15 + 10 = 100
So there are a total of 100 possible outcomes
Finally to find the probability of the pitcher throwing more than 3 pitches we divide favorable outcomes ( 25) by possible outcomes (100)
Our answer = 25/100 which can be converted into a percentage as 25%
Answer:
Pair of compasses.
Step-by-step explanation:
These are used to inscribe circles/arcs.
Compasses are used in maths, navigation,e.t.c.
Hope it helps.
1. The problem statement tells you to find "the area of the hexagonal face".
2. If we assume the intent is to find the shaded area of the face only, it differs from the area of a regular hexagon in that there is a hole in the middle.
3. You must find the area of the regular hexagon, and subtract the area of the circular hole in the middle.
4. The formula for the area of a circle in terms of its radius is
... A = πr²
5. The formula for the area of a regular hexagon in terms of the radius of the circumcircle is
... A = (3√3)/2·r²
6. The radius of the circumcircle of the regular hexagon is given. No additional information is needed.
7. You can use the trig functions of the angles of an equilateral triangle to find the apothem, but there is no need for that when you use the formula of 5.
8. All this is unnecessary. The apothem is (8 mm)·(√3)/2 = 4√3 mm ≈ 6.9282 mm, the shorter leg is (8 mm)·(1/2) = 4 mm. The perimeter is 6·8 mm = 48 mm.
9. The area of the hexagon is
... A = 3√3/2·(8 mm)² = 96√3 mm² ≈ 166.277 mm²
10. The area of the circle is
... A = π·(4 mm)² = 16π mm² ≈ 50.265 mm²
11. The area of the hexagonal face is approximately ...
... 166.277 mm² - 50.265 mm² = 116.01 mm²
Its 0.343 because it cannot be expressed as a fraction or whole number
