Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
3 cans
Step-by-step explanation:
We need to find the area of the deck
A = 9 1/9 * 3
Changing to an improper fraction
9 1/9 = (9*9+1)/9 = 82/9
A = 82/9 *3 = 82/3
Changing back to a mixed number
82/3 = 27 1/3
Each can covers 10 m^2
We will need 3 cans
Answer:
B. No
Step-by-step explanation:
In order for the relation to be a function, each X value must source exactly one arrow. The value -1 maps to two different values (2, -1), so the relation is NOT A FUNCTION.
None of the choices are equivalent
64/4 is 16
a is 4
b is 4
c is 2
d is 1
The answer is 2,925
to get the answer: 26*112=2912 .5 equals half an hour so half the pages
so you add 2912 + 13= 2925
