P and q are points on the line y=2-4X Draw the line y= 2-4X for vales of x from -2 to 2
1 answer:
Answer:
`The answer is below
Step-by-step explanation:
P and q are points on the line y=2-4X. complete the coordinates of P and Q, P(0, ) Q( ,0)
Draw the line y= 2-4X for vales of x from -2 to 2
Solution:
The equation of a line is given by:
y = mx + b
Where y and x are variables, m is the slope of the line and b is the y intercept (that is value of y when x = 0).
The line of y = 2 - 4x is drawn by finding the corresponding values of y for x from -2 to 2 and plotting on a graph.
x: -2 -1 0 1 2
y: 10 6 2 -2 -6
The value P(0, ) Q( ,0)
The y coordinate of point P is gotten by substituting x = 0:
y = 2 - 4(0) = 2
P = (0, 2)
The x coordinate of point Q is gotten by substituting y = 0:
0 = 2 - 4x
4x = 2
x = 0.5
Q = (0.5, 0)
You might be interested in
Answer:
Step-by-step explanation:
The input it taken as the unknown base value, while the output here is the area of the trapezoid. b is therefore the base value, and A( b ) is the area of the trapezoid. Let's formulate the equation for the area of the trapezoid, and isolate the area of the trapezoid. To find the inverse of this function, switch y ( this is A( b ) ) and b, solving for y once more, y ➡ y ⁻ ¹.
y = height ( ( unknown base value ( b ) + 7 ) / 2 ),
y = 10 ( ( b + 7 ) / 2 )
Now switch the positions of y and b -
b = 10 ( ( y + 7 ) / 2 ) or
- now that we are going to take the inverse ( y ⁻ ¹ ) or B( a ), b will now be changed to a,
,
Therefore the equation that represents the inverse function will be the following : B(a) = a / 5 - 7