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Verizon [17]
3 years ago
8

I need Advice preferably from 10th graders and up.

Mathematics
2 answers:
MissTica3 years ago
7 0

Answer:

Yes, when I was in middle school, my math grades were pretty bad. I always had a really hard time understanding my teacher's math lessons.

To overcome this,  I spent a lot of time on Khan Academy. The website is really useful, and it can help improve your math bit by bit. I gradually worked my way up, and I got on pace. Now I'm in 10th grade, and my math is much better.

A lot of times I wanted to give up because I thought it was a waste of time, but I think it was the peer pressure that pushed me forward. I did lots of khan academy over the summer in 8th grade, and now I'm much more confident about my math skills.

In the summer, I spent about an hour every day on khan academy, their courses are free and they are also understandable.

I wish you well in the future. It's better late than never.

Lera25 [3.4K]3 years ago
5 0

Life Advice:

I, too have experienced a huge fall in my math grades. I'm currently in high school and I have maybe 2 assignments done in my entire school year of math. I have almost no problem with any other subject, I just can't <em>motivate myself to do math</em>. I have a hard time ever even considering catching up, and I personally do not know if I will.

You might have the same problem I do, which is just lack of motivation.

If I were you I would provide some sort of incentive to get yourself to do it more efficiently and better yet, more enjoyably. I also advise listening to music that can get you in a good mood. Both of these things have been a huge help for me to stay motivated in other classes, and they may even help you with math.

I would also recommend getting some kind of a personal tutor. A friend, a worker at school, one of your math teachers. Never feel embarrassed to tell them you're behind. People will almost always be understanding when it comes to helping someone learn something they're behind on.

For an incentive, think about something you might be able to buy with money from a job that you take outside of high school, like a car or a house, or a guitar.

I, personally, am going to get a really beat-up pickup truck if it lasts till the end of my school year.

I hope this helped!

Thanks!

Your friend in life,

~Steve

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1. Jeremy has $12000 cash to invest in the bank compounded at 4% interest annually.
gavmur [86]

Answer:

A(x) = 12000(1.04)^x

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

$12000 cash

This means that P = 12000

Compounded at 4% interest annually.

This means that r = 0.04, n = 1

What equation will calculate the value in x years?

A(t) = P(1 + \frac{r}{n})^{nt}

A(x) = P(1 + \frac{r}{n})^{nx}

A(x) = 12000(1 + 0.04)^x

A(x) = 12000(1.04)^x

8 0
2 years ago
Is
elena55 [62]

Answer:

C. 0.300 s.

53

11 + x

Step-by-step explanation:

brainest plz

4 0
3 years ago
Read 2 more answers
Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
1 year ago
Which graph represents the function f (x) = StartFraction 4 Over x EndFraction?
beks73 [17]

Answer:

2nd graph (image)

Step-by-step explanation:

The function to graph is:

f(x)=\frac{4}{x}

It follows the general pattern of the function:  f(x)=\frac{1}{x}, which is general shape and in 1st and 3rd quadrants. So, we can eliminate 3rd and 4th choices (because of quadrants).

The answer is either 1st, or 2nd graph.

Now, we simply can check a point in both.

lets take x = 4, so the function would be:

f(4) = 4/4 = 1

Hence, point is:

(4,1)

The first graph doesn't go through this point. The second graph does.

hence, we can successfully choose the 2nd graph as our answer.

7 0
3 years ago
Read 2 more answers
An icicle has a volume of 3769.91 mm if this icicle Drips at a rate of 75 mm/min How long will it take the icicles completely me
kvasek [131]

Answer:

The answer is 3,019.92 cubic millimeter

Step-by-step explanation:

take 375 plus 375 to get 750

then 3769.91 - 750 to get the 3,019.92

3 0
3 years ago
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