All categories

3 years ago

A oil well is drilled at -175 meters ever 12 hours . How deep is the well after 15 hours of constant work. Numeric answers only

Mathematics

2 answers:

NikAS [45]3 years ago

6 0

Answer:

-37.5 m

Step-by-step explanation:

If we assume that "one full day" is 24 hours, then 15 hours represents the fraction 15/24 of a day. Since the drilling rate was constant, and was presumed to start from a height of 0, the height after 15 hours is that fraction of the day's work:

... (15/24)×(-60 m) = -37.5 m

Nat2105 [25]3 years ago

5 0

Answer:

-218.75

Step-by-step explanation:

you probably don't need the answer anymore but I still thought I should put it out there

You might be interested in

What is (9+8)/(88+77)

barxatty [35]

Answer:

Exact form: 17/165

Decimal form: 0.103

Step-by-step explanation:

hope this helps :)

3 0

3 years ago

Read 2 more answers

Can someone just answer these lol idk what to say .

Crank

Answer:

1.) -11x 2.)-2x

4 0

3 years ago

Read 2 more answers

Plz help with multiple choice

nikitadnepr [17]

Answer:

Step-by-step explanation:

Assume both their ages are $J$

One is 3 years older than the other, and the sum of their ages add up to 19

$J+J+3=19$

5 0

3 years ago

Read 2 more answers

✓<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B19%20%2B%20%20%5Csqrt%7B30%20%2B%20%20%5Csqrt%7B32%20%2B%20x%20%20%7D%20%7D%

Setler79 [48]

We'll have to repeatedly square both sides of the equation, in order to get rid of the square roots. Squaring a first time yields

$19+\sqrt{30+\sqrt{32+x}}=25$

Move the 19 to the right hand side:

$\sqrt{30+\sqrt{32+x}}=6$

And square again:

$30+\sqrt{32+x}=36 \iff \sqrt{32+x}=6$

Square one last time:

$32+x=36 \iff x=36-32=4$

Let's check the solutions: all these squaring might have created external solutions:

$\sqrt{19+\sqrt{30+\sqrt{32+4}}}=\sqrt{19+\sqrt{30+6}}=\sqrt{19+6}=\sqrt{25}=5$

So, $x=4$ is a feasible solution.

8 0

3 years ago

In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AH=4 and HC=1, find BH.

Rudik [331]

Answer:

Length of BH is 2 units.

Step-by-step explanation:

We have, ΔABC with ∠ABC = 90° and an altitude BH.

Also, it is given that the length of sides AH is 4 units and HC is 1 units.

Since, the 'Altitude Rule' states that 'the length of the altitude is the geometric mean of the line segments it bisects'.

So, we get that,

$BH^{2}=AH\times HC$

i.e. $BH^{2}=4\times 1$

i.e. $BH^{2}=4$

i.e. $BH=\pm 2$

Since, the length of the side cannot be negative.

So, length of BH is 2 units.

3 0

3 years ago