A standard cube has 6 possible outcomes. But since we want to find P(4+ or odd), the outcomes become more narrow.
So:
6 outcomes -> 1, 2, 3, 4, 5, 6
But we want to find 4+
So:
4+ = 4, 5, 6
We also want to find all odd possibilities.
So:
odd = 1, 3, 5
As you can see, there is a 5 in both the 4+ and the odd numbers so 5 will only be counted once.
P(4+ or odd) = 1, 3, 4, 5, 6
So the probability of having an outcome that is P(4+ or odd) is:
5/6 or 0.8333 or 83.33%
Hope I helped!
Answer:
step three
Step-by-step explanation:
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(even if it’s a joke I want points)
Answer:
Step-by-step explanation:
The Hypothesis :
H0 : σ = 10
H1 : σ ≠ 10
The Chisquare statistic, χ² ;
χ² = [(n-1) * s²] ÷ σ²
Sample size, n = 44 ; sample Standard deviation, s = 10.7 ; population standard deviation, σ = 10
χ² = [(44 - 1) * 10.7²] ÷ 10²
χ² = [43 * 114.49] ÷ 100
χ² = [4923.07] ÷ 100
χ² = 49.2307
Using the Pvalue from Chisquare calculator :
degree of freedom, df = n - 1 = 44 - 1 = 43
Pvalue = 0.238
Step-by-step explanation:
volume of cylinder =π r²h
= 3.14 × 17×17×16
= 14519.31 inches square .
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