I solved it on your other posting of it. x = 12
All of the steps are there
        
                    
             
        
        
        
Step-by-step explanation:
6ac+10ac
2ac(6ac+10ac)
2ac(3+5)
 
        
             
        
        
        
Answer:
jjsjwnen e enejwjjqjqjjwneje
 
        
             
        
        
        
We will be using the fact that  , where
, where  is the probability that the first bulb works and
 is the probability that the first bulb works and  is the probability that the second bulb works.
 is the probability that the second bulb works.
The probability that the first bulb works is  . However, when we take one out (given that the first bulb works) we now have 19 working bulbs and 4 bad ones. This means that the probability that the second bulb works is
. However, when we take one out (given that the first bulb works) we now have 19 working bulbs and 4 bad ones. This means that the probability that the second bulb works is  .
.
Now, we can find our final probability:
