<u>Man-in-the-middle attack</u> refers to a type of an attack in which an attacker makes his data look like it is coming from a different source address, and is able to intercept information transferred between two computers.
<u>Explanation:</u>
A man-in-the-middle attack (MITM) is an assault where the aggressor furtively transfers and potentially changes the correspondences between two gatherings who accept that they are straightforwardly speaking with one another. This happens when the assailant catches a segment of a correspondence between two gatherings and retransmits it sometime in the future. The assailant would then be able to screen and perhaps change the substance of messages. The utilization of such encoded burrows makes extra secure layers when you get to your organization's secret systems over connections like Wi-Fi.
The answer is A B AND D mark me brainliest?
Answer:
import java.util.Scanner;
public class ss11{
public static void main (String[]args) {
Scanner keyboard = new Scanner (System.in)
String a1, a2, a3, a4, a5;
int i1, i2, i3, i4, i5;
System.out.println("Enter a four bit binary number:");
a1= keyboard.next();
a2= a1.substring(0,1);
a3= a1.substring(1,2);
a4= a1.substring(2,3);
a5= a1.substring(3,4);
i1 = Integer.parseInt(a2);
i2 = Integer.parseInt(a3);
i3 = Integer.parseInt(a4);
i4 = Integer.parseInt(a5);
i1= i1 * 8;
i2= i1 * 4;
i3= i1 * 2;
i4= i1 * 1;
i5= i1+i2+i3+i4;
System.out.println("The converted decimal number is: +i5);
}
}
Explanation:
I = V/R. So the answer is 9/200 = 0.045A = 45mA which is B
Programming languages im pretty sure
