3 years ago

Log x^4-logx^3=log 3x-log2x solve

Mathematics

1 answer:

lesya692 [45]3 years ago

7 0

Answer:

x = 3/2

Step-by-step explanation:

Log x^4-logx^3=log 3x-log2x solve

log(x^4/x^3) = log(3x/2x)

Log cancels out

x^4/x^3 = 3x/2x

x^3 * x/x^3 = 3/2

x^3/x^3 * x = 3/2

x = 3/2

Hence the required value of x is 3/2

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Log x^4-logx^3=log 3x-log2x solve​

Log x^4-logx^3=log 3x-log2x solve