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Genrish500 [490]
3 years ago
7

Find the geometric of 5,8,9,12,15​

Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

mom this u?

Step-by-step explanation:

You might be interested in
How many solutions does the system have?
amid [387]

Answer:

A; infinitely many solutions

Step-by-step explanation:

first, let's simplify the first equation to make it simpler.

divide both sides by 5

y=3x-8

new system

y=3x-8

y=3x-8

as you can see, they are the same.

not mandatory but useful!⬇⬇⬇⬇

just to be more clear, let's substitute them. since they're both already in y=, we can make them both set to each other.

3x-8=3x-8

add 8 to both sides; subtract 3x from one side

0=0

the answer is A, Infinitely many solutions.

hope this helped <3333333

8 0
3 years ago
Please help I will mark brainlist if correct
djyliett [7]
Solving for L:

P = 2L + 2W
P - 2W = 2L
(P - 2W) / 2 = L
L = (P - 2W) / 2
8 0
3 years ago
Fiona’s Number:
Amanda [17]

Answer:

He should dial 289-743-1560

Step-by-step explanation:

The first three digits:  "My first three digits are the square of an integer less than twenty"

Step 1:   We can get the first three by looking at the squares of the integers from 1 to 19.  We need a three digit number, so starting with 10, since 10² = 100, we list the squares of the integers from 10 to 19

10² = 100

11² = 121

12² = 144

13² = 169

14² = 196

15² = 225

16² = 256

17² = 289

18² = 324

19² = 361

Step 2:  "The first three digits are in ascending order" and no digits can repeat, so we eliminate the answers above that don't satisfy both of these condintions.  This leaves just 3 choices:

13² = 169

16² = 256

17² = 289

*We will come back to this once we have more information.

The last 2 numbers: "the last two digits are multiples of sixty".  

The only 2 digit number that is a multiple of 60 is 60, so 6 and 0 are the last 2 digits.  This rules out two answers from Step 1 since no digits can repeat.  Only 289 works since 169 and 256 each have a 6 in them.  So now we know the first 3, and last 2 numbers!

                                     2 8 9 _ _ _ _ _ 6 0

The last 4 numbers: "the last 4 digits are multiples of sixty"

We want to find a 4 four digit number that has 60 as the last 2 digits.  Notice a pattern when you multiply 60 by certain digits...

60 x 1 = 60

60 x 2 = 120

...

60 x 6 = 360

60 x 11 = 660

60 x 16 = 960     (these all don't work since they are not 4 digits)

60 x 21 = 1260     (this is the first 4 digit result, but it doesn't work because

                              there is a '2' in it, and 2 has already been used as the

                               first digit of the number)

60 x 26 = 1560     (this number could work, so lets try it and see if we can

                               satisfy the rest of the statements)

Now our number is

  2 8 9 _ _ _ 1 5 6 0

The second three digits:  "The second three digits are in descending order"  and "The sum of the second three digits is 14"

If we assume that 1, 5, 6 and 0 are the last four digits, we know that 2, 8 and 9 are the first three digits, this leaves 3, 4 and 7 as the three remaining digits.  

3 + 4 + 7 = 14     so that condition is satisfied.   We just need to write then in descending order, so our final number is

289-743-1560

3 0
3 years ago
Read 2 more answers
Helppppp someone answered the first half but I need the second half
Roman55 [17]

Answer:

i think its 182 dollars

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
1 + x to the 0th power.
lutik1710 [3]
Is 0 because it's to the power of zero
8 0
3 years ago
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