Which polynomial is a perfect square trinomial?

1 answer:

5 0

The definition of a perfect square trinomial:
When a square of a number (3*3=9) can also add up to another number in the trinomial (3+3=6)

In my example here the equation, in order to be a perfect square trinomial, would be: X^2+6y+9

Now to look at the problem. We can instantly single out C because 10*10 is 100 but 10+10 is not five.
If we look at A we can find the root of 25 (5) but 5+5 is 10 not five. So A is incorrect
Using our previous calculation we know that 5 is our magic number. Leaving us with B and D. If we look at D we can conclude that -5*5 would be -25 but -5+5 is zero. So, it is not D
Using power of elimination we can easily conclude that B is the correct answer. If you wish to check: (5+5=10) (5*5=25)

Answer: B

Hope this helped!

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Two parallel lines are crossed by a transversal. What is the value of D?

Sliva [168]

Answer:c

Step-by-step explanation:

4 0

3 years ago

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Suppose f(x) = x^2 and g(x) = (1/4)^2. Which statement best compares the graph of g(x) with the graph of f(x)

hjlf

Answer:

g(x) is the image of f(x) after stretched horizontally by scale factor = 4

Step-by-step explanation:

The statement that best compares the graph of g(x) with the graph of f(x) says g(x) is the image of f(x) after stretched horizontally by scale factor = 4 because:

Given the function

f(x) = x² and g(x) = (1/4x)² the image of f(x) after one transformation.

The transformation shows that g(x) stretches away from y-axis.

Since the transformation is stretched horizontally. So g(x) is the image of f(x) after stretched horizontally by scale factor (I.e. by 1).

Then we use the scale factor to divide g(x)

1 ÷ ¼ = 1 x 4/1 = 4

So therefore, g(x) is the image of f(x) after stretched horizontally by scale factor = 4

8 0

4 years ago

15 points!!! GEOMETRY help please!! Questions attached!

marishachu [46]

9.
$\text{If QR is tangent to circle then m}\angle PQR=90^o$

$\text{We can use the converse of Pythagorean theorem}$

$8\ and\ 4\sqrt3\\\\check:\ 4^2+(4\sqrt3)^2=8^2\\16+16\cdot3=64\\16+48=64\\64=64\ -O.K.\\\\2\ and\ 4\sqrt2\\\\check:\ 4^2+2^2=(4\sqrt2)^2\\16+4=16\cdot2\\20=32\ -FALSE\\\\3\ and\ 5\\\\check:\ 3^2+4^2=5^2\\9+16=25\\25=25\ -O.K.\\\\2\ and\ 2\sqrt5\\\\check:\ 4^2+2^2=(2\sqrt5)^2\\16+4=4\cdot5\\20=20\ -O.K.\\\\6\ and\ 10\\check:\ 4^2+6^2=10^2\\16+36=100\\52=100\ -FALSE$

$\text{Answer:}\boxed{8\ and\ 4\sqrt3;\ 3\ and\ 5;\ 2\ and\ 2\sqrt5}$

10.
$\text{Look at the pictures}$

$\text{Therefore}\\\\C=2\cdot8+2\cdot16+2\cdot9+2\cdot6=16+32+18+12=78cm$

$Other\ method:\\C=2\cdot(8+16+6+9)=2\cdot39=78cm$