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3 years ago

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A Salesman worked on a weekly salary of $180.00 . To this was added a commission of 5% on all sales over $500. It his sales for

one week were $750, his total salary for the week was?

1 answer:

Anvisha [2.4K]3 years ago

4 0

250x.05 = 12.5 + 180 = 192.50

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Plz help Large cheese pizzas cost $5 each and large one-topping pizzas cost $6 each write an equation that represents the total

Komok [63]

Answer:

T = 5c +5d, where unit of the equation is $.

Step-by-step explanation:

Cost of 1 large cheese pizza = $5

No. of large cheese pizza = c

therefore

cost of c large cheese pizza = c*Cost of 1 large cheese pizza = $5c

Cost of 1 large one topping pizza = $6

No. of large one topping pizza = d

therefore

cost of d large one topping pizza = d*Cost of 1 large one topping pizza = cost of d large one topping pizza = $6d

Total cost of c large cheese pizza and cost of d large one topping pizza

= $5c +$6d

total cost is represented by T

thus, T = $5c +$5d Answer

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3 years ago

Sally designs web pages. She charges $140 per web page. She also needs to pay

dolphi86 [110]

You will take 140 times 5 since that is the amount she made so you times it buy the price she earns then after you do that subtract it buy 650 since that is what you have to pay
140 x 5 = 700
700 - 650 = 50
so she made a profit of 50

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3 years ago

A greater number than -8

sertanlavr [38]

Practically anything above -8
Such as -7, 2, 15600, anything not under -7.9

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3 years ago

Please help with this problem :(

Lilit [14]

36 - 24

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8 0

3 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

3 years ago