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statuscvo [17]
3 years ago
14

Solve for x 14x = 5(2x – 4) – 12

Mathematics
2 answers:
ehidna [41]3 years ago
3 0
The answer is
X = - 8
Sergeeva-Olga [200]3 years ago
3 0

Answer:

x=3

Step-by-step explanation:

14x= 5(2x-4) - 12

14x= 10x - 20 - 12

14x= 10x -8

24x= 8

x= 3

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3(5x + 7) <br><br> Use the distributive property to simplify each expression.
Tomtit [17]

Answer: 15x+7

Step-by-step explanation:

you multiply 3 by 5 and add 7

3 0
3 years ago
What is the first step in finding the unit price on a box of 20 pencils?
olga55 [171]

You would need to know the cost of the box of 20, then you would divide the total cost by the number of pencils in the box. This would give you the cost of one pencil - which is the unit cost.


Example:

Lets say the box of 20 pencils cost $10.


Divide the total cost by the number of pencils:

10 / 20 = 0.50 - This means each pencil cost 50 cents, so the unit cost would be 50 cents per pencil.

7 0
3 years ago
What is the extended ratio relating the side lengths of a 45-45-90 triangle?
Zanzabum

Answer:

RIGHT ANGLES

Step-by-step explanation:

There are two types of special right triangles, based on their angle measures. The first is an isosceles right triangle. Here, the legs are congruent and, by the Base Angles Theorem, the base angles will also be congruent. Therefore, the angle measures will be 90∘,45∘, and 45∘. You will also hear an isosceles right triangle called a 45-45-90 triangle. Because the three angles are always the same, all isosceles right triangles are similar.

7 0
4 years ago
Read 2 more answers
Find a homogeneous linear differential equation with constant coefficients whose general solution is given by
frez [133]

Answer:

y" + 2y' + 2y = 0

Step-by-step explanation:

Given

y=c_1e^{-x}cosx+c_2e^{-x}sinx

Required

Determine a homogeneous linear differential equation

Rewrite the expression as:

y=c_1e^{\alpha x}cos(\beta x)+c_2e^{\alpha x}sin(\beta x)

Where

\alpha = -1 and \beta = 1

For a homogeneous linear differential equation, the repeated value m is given as:

m = \alpha \± \beta i

Substitute values for \alpha and \beta

m = -1 \± 1*i

m = -1 \± i

Add 1 to both sides

m +1= 1 -1 \± i

m +1= \± i

Square both sides

(m +1)^2= (\± i)^2

m^2 + m + m + 1 = i^2

m^2 + 2m + 1 = i^2

In complex numbers:

i^2 = -1

So, the expression becomes:

m^2 + 2m + 1 = -1

Add 1 to both sides

m^2 + 2m + 1 +1= -1+1

m^2 + 2m + 2= 0

This corresponds to the homogeneous linear differential equation

y" + 2y' + 2y = 0

6 0
3 years ago
1/5 *6x-3=1/10(6x+12)​
Veseljchak [2.6K]

Answer:

x = 7

Step-by-step explanation:

We solve the equation the following way...

\frac{1}{5}6x - 3 = \frac{1}{10}(6x + 12)\\1.2x = 0.6x + 1.2 + 3\\1.2x - 0.6x = 1.2 + 3\\0.6x = 4.2\\6x = 42\\x = 7

4 0
3 years ago
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