Question

358. Now consider the family of lines ax + by = c such that a, b and c are consecutive multiples

Answer 1

Any subsequence of consecutive integers of length 9 that has a term ... Assume now that we have found an n-digit number m divisible by 2n made out of ... the set of ordered triples of people (a, b, c) such that c is either a ... again we have two families of lines, but such that M1j are all of the same color; ... a1(x)x2 − ax(x)x = 0.