Question

The perimeter of a square is 56cm. What is the approximate length of its diagonal?

Answer 1

4. 19.8
56/4=14
Diagonal of a square is equal to one side multiplied by the square root of two.
Therefore, it is 19.8, being that square root is (in super simple rounding) 1.5.

Answer 2

Answer:

17.8 cm is the approximate length of its diagonal.

Step-by-step explanation:

Side of the square = l

Perimeter of the square = P = 56 cm

Perimeter of the square is the sum of all the sides of the square.

4a = 56 cm

$4a=56 cm$

$a=\frac{56}{4}=14 cm$

The length of the diagonal is given by: d

$d^2=a^2+a^2$ (Pythagoras theorem)

$d=\sqrt{a^2+a^2}=\sqrt{2a^2}$

$d=17.79 cm\approx 17.8 cm$

17.8 cm is the approximate length of its diagonal.