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mart [117]
3 years ago
14

Exponential Growth/Decay Plz help!!!

Mathematics
1 answer:
ollegr [7]3 years ago
4 0

Answer:

a) 82.

b) So a growth factor of 0.025

c) 2.5%.

d) f(5) = 93, which means that the population of the island on January 1st 2026 is of 93.

Step-by-step explanation:

Exponential equation of population growth:

The exponential equation for population growth has the following format:

f(x) = x(0)(1+r)^x

In which x(0) is the initial value and r is the growth factor, as a decimal.

In this question:

In x years after 2021:

f(x) = 82(1.025)^x

a)

This is f(0). So

f(0) = 82(1.025)^0 = 82

So 82.

b)

We have to find r. So

1 + r = 1.025

r = 1.025 - 1 = 0.025

So a growth factor of 0.025.

c)

Growth factor multiplied by 100%.

So 0.025*100% = 2.5%.

d)

f(5) = population in 5 years after January 1st 2021, that is, January 1st 2026.

f(5) = 82(1.025)^5 = 93

f(5) = 93, which means that the population of the island on January 1st 2026 is of 93.

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which expression is equivalent to the given expression after using the distributive property 6*13+6*7
egoroff_w [7]

Answer: 6*(13+7) = 60


Step-by-step explanation:

6*13+6*7

6*(13+7) = 6*10 =60

5 0
3 years ago
A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m
arsen [322]

Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let <em>X</em> = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.

The sample of employed individuals selected is of size, <em>n</em> = 225.

An individual holding multiple jobs is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.

Conditions of Normal approximation to Binomial are:

  • np ≥ 10
  • n (1 - p) ≥ 10

Check the conditions as follows:

np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10

The distribution of the proportion of individuals who hold multiple jobs is,

p\sim N(p, \frac{p(1-p)}{n})

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

P(p

*Use a <em>z</em>-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

7 0
3 years ago
Pls helppppppppppp i give points
d1i1m1o1n [39]
The answer you selected in that photo given, is correct. I can tell just by using common sense and by judging the other options second option (B) is looking the most clearest one to me.
8 0
2 years ago
Please help. 50 points + brainliest
Korvikt [17]

Answer:

1. (a-c)\sqrt{x} + b\sqrt{y}

2. 9m + 2\sqrt{n}

3. 6a

4. (5a - 3b)\sqrt{5y}

Step-by-step explanation:

1. since a and c share the same squareroot x, you can combine these together.

2. First add like terms together. 4m - m + 6m = 9m. Then 5\sqrt{n} and -3\sqrt{n} combined equals 2\sqrt{n}

3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a

4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:

5a\sqrt{5y} - 3b\sqrt{5y}

We can combine the two like terms and get the final answer above.

please give thanks by clicking the heart :)

3 0
3 years ago
What is 7.55×8 please show work
iVinArrow [24]
Is this Long multiplication?
7 0
3 years ago
Read 2 more answers
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