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2 years ago

Can someone please work out both problems, I need help with my math hw due in 4 hours

Mathematics

1 answer:

jenyasd209 [6]2 years ago

4 0

Answer:

I hope this helps

Step-by-step explanation:

This is not the same exact question but it shows you the throw down.

A+B+C= 180

so if A=60 and B=70

The sin is= 8

so 60+70= 130

130+c=180

130-180= 50

C=50

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The cost of 1 watermelon and 5 oranges is $11.The cost of 3 watermelons and 5 oranges is $24.50.How much is the cost of 1 waterm

nignag [31]

Answer:

$6.75

Step-by-step explanation:

1: In this explanation, let's let one watermelon be w, and one orange be o.

2: From the passage, 1w + 5o = $11.

3: Also from the passage, 3w + 5o = $24.50

4: We can then use a simultaneous equation to work them out - both equations we have use 5 oranges.

3w + 5o = 24.5 (equation 1)

1w + 5o = 11 (equation 2)

5: We can now take the second equation away from the first :

3w - 1w = 2w, 5o - 5o = 0, 24.5 - 11 = 13.5

Now we know 2w = 13.5

6: If 2w = $13.50, one watermelon will be half of that, so $6.75

Hope this helps, let me know if you have any further questions :)

8 0

1 year ago

If the first and the last terms of an arithmetic series are 10 and 62, show that the sum of the series varies directly as the nu

Nitella [24]

Answer:

10+^@=72_^) + the series

Step-by-step explanation:

6 0

2 years ago

Sam shot the basketball 15 times. 40% of his shots were made. How many shots did Sam make?

love history [14]

Answer:

Step-by-step explanation:

40% is equal to 40/100

He made 40% of 15 shots so you miltiply 15 by 40/100 which is equal to 6.

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1 year ago

Read 2 more answers

WILL MARK BRAINLIEST IF BOTH CORRECT!! PLEASE ANSWER!! 6TH GRADE MATH NYC??

fenix001 [56]

Answer:

19. c 20.b

Step-by-step explanation:

5 0

2 years ago

(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim

aleksklad [387]

(i) Given that

$V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr$

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

$V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}$

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

$\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

Compute the integral:

$V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

$V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr$

$V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R$

$V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)$

$V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}$

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0

2 years ago