Question

3^x+1=sqrt3 1" title=" {3 }^{x + 1} = \sqrt{3} " alt=" {3 }^{x + 1} = \sqrt{3} " align="absmiddle" class="latex-formula">
Help plz​

Answer 1

Answer:

value of x = -1 / 2

or

$\frac{ - 1}{2}$

Step-by-step explanation:

here's the solution :-

=》

$3 {}^{x + 1} = \sqrt{3}$

=》

$3 {}^{x + 1} = 3 {}^{ \frac{1}{2} }$

( since, root 3 = 3^1/2 )

=》

$x + 1 = \frac{1}{2}$

=》

$x = \frac{1}{2} - 1$

=》

$x = \frac{ - 1}{2}$

Answer 2

Answer:

√3= $\sqrt[2]{3}$=$3^{\frac{1}{2} }$

x+1=1/2

x=1/2-2/2=$\frac{-1}{2}$

Step-by-step explanation:

Hope it helps!