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Archy [21]
3 years ago
6

3^x+1=sqrt3

1" title=" {3 }^{x + 1} = \sqrt{3} " alt=" {3 }^{x + 1} = \sqrt{3} " align="absmiddle" class="latex-formula">
Help plz​
Mathematics
2 answers:
pogonyaev3 years ago
7 0

Answer:

value of x = -1 / 2

or

\frac{ - 1}{2}

Step-by-step explanation:

here's the solution :-

=》

3 {}^{x + 1}  =  \sqrt{3}

=》

3 {}^{x + 1}  = 3 {}^{ \frac{1}{2} }

( since, root 3 = 3^1/2 )

=》

x + 1 =  \frac{1}{2}

=》

x =  \frac{1}{2}  - 1

=》

x =  \frac{ - 1}{2}

ivanzaharov [21]3 years ago
5 0

Answer:

√3= \sqrt[2]{3}=3^{\frac{1}{2} }

x+1=1/2

x=1/2-2/2=\frac{-1}{2}

Step-by-step explanation:

Hope it helps!

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