70/81 is 7/81+7/9 as a proper fraction
Remark
You don't have to decompose the second one, and it is better if you don't. Just find the area as you probably did: use the formula for a trapezoid. You have to assume that the 6cm line hits the 2 bases at right angles for each of them, otherwise, you don't know the height. So I'm going to assume that we are in agreement about the second one.
Problem One
The answer for this one has to be broken down and unfortunately, you answer is not right for the total area, although you might get 52 for the triangle. Let's check that out.
<em><u>Triangle</u></em>
Area = 1/2 * b * h
base = 16 cm
h = 10 - 4 = 6
Area = 1/2 * 16 * 6
Area = 48
<em><u>Area of the Rectangle</u></em>
Area = L * W
L = 16
W = 4
Area = L * W
Area = 16 * 4
Area = 64
<em><u>Total Area</u></em>
Area = 64 + 48
Area = 112 of both figures <<<< Answer
Question 6
Given:
QR = RS
QR = x + 6
RS = 4x
To find:
Length of line segment QS
Steps:
We know QR = RS, so substituting we get,
x + 6 = 4x
6 = 4x - x
6 = 3x
6/3 = x
2 = x
x = 2
Now,
QS = QR + RS
QS = x + 6 + 4x
QS = 2 + 6 + 4(2)
QS = 2 + 6 + 8
QS = 8 + 8
QS = 16 units
Therefore, the length of QS is 16 units
Question 7
Given:
QR = RS
QR = 2x - 2
RS = 2x
To find:
Length of line segment QS
Steps:
We know that QR = RS, so substituting the values we get,
QR = RS
3x - 2 = 2x
3x - 2 - 2x = 0
3x - 2x = 2
x =2
Now,
QS = QR + RS
QS = 3x - 2 + 2x
QS = 3(2) - 2 + 2(2)
QS = 6 - 2 + 2(2)
QS = 6 - 2 + 4
QS = 4 + 4
QS = 8 units
Therefore, the length of QS is 8 units
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