we know that
Two angles are supplementary if their sum is equal to 
degrees
in this problem we have
so
therefore
<u>the answer is</u>
The two angles are supplementary
I solved this using a scientific calculator and in radians mode since the given x's is between 0 to 2π. After substitution, the correct pairs
are:
cos(x)tan(x) – ½ = 0
→ π/6 and 5π/6
cos(π/6)tan(π/6) – ½ = 0
cos(5π/6)tan(5π/6) – ½ = 0
sec(x)cot(x) + 2 =
0 → 7π/6 and 11π/6
sec(7π/6)cot(7π/6) + 2 = 0
sec(11π/6)cot(11π/6) + 2 = 0
sin(x)cot(x) +
1/sqrt2 = 0 → 3π/4 and 5π/4
sin(3π/4)cot(3π/4) + 1/sqrt2 = 0
sin(5π/4)cot(5π/4) + 1/sqrt2 = 0
csc(x)tan(x) – 2 = 0 → π/3 and 5π/3
csc(π/3)tan(π/3) – 2 = 0
csc(5π/3)tan(5π/3) – 2 = 0
Answer:
Step-by-step explanation:
We have
square with sides <em>s = 3cm</em>
four triangles with base <em>b = 3cm</em> and height <em>h = 9cm</em>.
The formula of an area of a square:
The formula of an area of a triangle:
Substitute:
The Surface Area:
Answer:
10x-6+y
Step-by-step explanation:
remove parentheses then collect like terms,hope this helped:)
I got 0-5
Sorry if I’m wrong I try
